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Hatshy [7]
3 years ago
11

√37 < 5 1/4 (true or false)

Mathematics
1 answer:
Alex787 [66]3 years ago
4 0
OK so on the top problem, the first thing you want to do is find the √37, once you know the answer to that you can compare it to 5 1/4 then it will be much easier to see is in fact √37 less than 5 1/4 or not.

On the bottom you want to know if 15 over the square root of ten is greater than 8.38 so what you want to do is to first find the square root of ten. after you know this then you put that number under 15. then you can compare what ever 15÷√10 is to 8.83. if you need any more info let me know.
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Help solve for r algebra
bija089 [108]

Answer:

\frac{20}{7}

Step-by-step explanation:

Multiply both sides by 7 to get rid of the denominator on the Right Side (RS). Do the same for the left side (LS) by multiplying both sides by 5 to get:

7r=4(5)

Simplify: 7r=20

Divide both sides of the equation by 7 to get: r=\frac{20}{7}

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3 years ago
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Read 2 more answers
Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has
Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8  

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

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3 years ago
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photoshop1234 [79]

Answer:

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Step-by-step explanation:

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Use photmath app it will help you out:)
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