Given expression: 
for x = 3 and y = –2
(6) Mistake did by Grayson:
In second step, first to do 3² and then multiply with 4.
But Grayson first multiply 4 with 3 and then squared the expression.
This is wrong.
(7) Mistake did by Emily:
In third step, first to multiply 2 with (–2) using BODMAS rule and then add with 36.
But Emily first added 36 with 2 which gives 38.
This is wrong.
(8) Mistake did by Pat:
In first step, the y value given is –2.
But Pat substituted y value is 2.
This is wrong.
(9) Correct evaluation:
This is the correct way to evaluate the given expression.
X - the number
The two possible solutions are
-3 or 4.
1. ( y - 0)/( -2 - 0) = (x - 0)/(1 - 0);
Then, y/(-2) = x/1;
finalyy, y = -2x;
The correct answer is B.
2. In the same way, we obtain y =4x; the correct answer is A.
Answer:
Multiply the radius or diameter by 2.
Step-by-step explanation:
Because there is no drawing, I will tell you what to do. A scale factor means multiply all the dimensions by [some number]. The scale factor is 2, so you will need to multiply the radius or diameter by 2.
By working with the velocity vectors, we will find that the direction of motion of the plane is 28.7 south of east.
Working with the velocity vectors:
First, we need to define our coordinate axis, I will define the x-axis as the east and the y-axis as the north.
We know that the plane travels at 150 mi/hr at 100° east of north, notice that if we measure from the positive x-axis, this is equivalent to an angle of -10°.
Then the x-component of the velocity is: 150mi/hr*cos(-10°) = 147.7 mi/hr
The y-component of the velocity is: 150mi/hr*sin(-10°) = -26 mi/hr.
So the vector is:
V = < 147.7 mi/hr, -26 mi/hr >
Now we know that the wind blowing at 50mi/hr at southwest, exactly southwest would be at an angle of 225°, so the components of the vector are:
x-component: 50mi/hr*cos(225°) = -35.4 mi/hr
y-component: 50mi/hr*sin(225°) = -35.4 mi/hr.
So the vector is:
W = < -35.4 mi/hr, -35.4 mi/hr>
The sum of the vectors gives the total velocity of the plane in the wind, we will get:
V + W = < 147.7 mi/hr -35.4 mi/hr , -26 mi/hr -35.4 mi/hr >
V + W = <112.3 mi/hr, -61.4 mi/hr>
The direction of a vector is given by:
θ = Atan(y/x)
Then in this case the direction of the plane is:
θ = Atan(-61.4 mi/hr/112.3 mi/hr) = -28.7°
So the direction of the plane is 28.7° south of east.
