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3 years ago

Who is able to pass out flyers at a faster rate

Mathematics

2 answers:

Anna11 [10]3 years ago

7 0

Please provide more information

Alexxandr [17]3 years ago

6 0

Answer:

I don't know because you did not provide enough info

Step-by-step explanation:

but personally I think that I could pass the flyers out the fastest

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Shobos mother present age is six times shobos present age. Shobos age five from now will be one third of his mother's present ag

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equations:

$M = 6S$

$S + 5 = \frac{1}{3}M$

where $S$ is the current age of Shobos and $M$ is the current age of his mother.

Substituting the first equation into the second will allow us to solve for $S$ :

$S + 5 = \frac{1}{3}M$

$S + 5 = \frac{1}{3}(6S)$

$S + 5 = 2S$

$S = 5$

Substituting this value into the first equation gives us the age of the mother:

$M = 6S$

$M = 6(5)$

$M = 30$

5 0

3 years ago

Read 2 more answers

Dali rolled up his painting and placed it in a cylinder 2 inches diameter. If the cylinder is 20 inches long find its volume. Ro

alekssr [168]

Answer:

The correct answer is 63 cubic inches.

Step-by-step explanation:

Dali rolled up his painting and placed it in a cylinder 2 inches diameter.

Diameter of the painting is 2 inches. This also implies diameter of the cylinder is 2 inches.

Radius of the cylinder is 1 inch.

Length of the cylinder is 20 inches.

Volume of the cylinder is given by π × $r^{2}$ × h = π × $1^{2}$ × 20 = 20π = 62.85 cubic inches ≈ 63 cubic inches.

Therefore the volume of the cylinder in which Dali placed his painting is given by 63 cubic inches.

3 0

3 years ago

Does anyone know how to solve this? It’s really starting to stress me out.

bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0

3 years ago

Tickets for 2 adults and 4 children at a theme park cost £152.

beks73 [17]

hope it helps!!!!

please mark brainliest

5 0

3 years ago

Read 2 more answers

Twenty five is the quotient of a number y and 3.5

Vilka [71]

Y/3.5= 25

(Hoped this help^)

8 0

3 years ago