Question

Find P(0), P(1) and P(2) for each of the following polynomial.

Answer 1

Step-by-step explanation:

p(y)=2+y+2y²-y³

p(0)=2+(0)+2(0)²-(0)³=2+0+0-0=2

p(1)=2+(1)+2(1)²-1³=2+1+2-1=4

p(2)=2+2+2(2)²-2³=4+8-8=4

HOPE IT HELPS YOU

Answer 2

$\sf \: p(y) = 2 + y + 2y {}^{2} - y {}^{3}$

$\sf \: p(o) = 2 + (o) + 2(o) {}^{2} - (o) {}^{3} = 2 + 0 + 0 - 0 = 2$

$\sf \: p(1) = 2 + (1) + 2(1) {}^{2} - 1 {}^{3} = 2 + 1 + 2 - 1 = 4$

$\sf \: p(2) = 2 + 2 + 2(2) {}^{2} - 2 {}^{3} = 4 + 8 - 8 = 4$