Answer:
x = ±2√15
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
x² = 60
<u>Step 2: Solve for </u><em><u>x</u></em>
- Square root both sides: x = ±√60
- Simplify: x = ±2√15
<u>Step 3: Check</u>
<em>Plug in both solutions of x to verify it's a solution.</em>
x = 2√15
- Substitute: (2√15)² = 60
- Evaluate: 4 · 15 = 60
- Multiply: 60 = 60
x = -2√15
- Substitute: (-2√15)² = 60
- Evaluate: 4 · 15 = 60
- Multiply: 60 = 60
Here we see that both solutions do indeed work.
∴ x = ±2√15 are both solutions to the equation.
Answer:
x = 7
Step-by-step explanation:
The segment from the centre at right angles to the chord, bisects the chord, so
x = 7
Answer:
I would say B go with ur best bet
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