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2 years ago

How many minutes are in 5/6, 1/2, and 2/3 of an hour

Mathematics

2 answers:

ss7ja [257]2 years ago

8 0

5/6 of an hour = 50 minutes.
1/2 of an hour = 30 minutes.
2/3 of an hour = 40 minutes.

julia-pushkina [17]2 years ago

5 0

An hour has 60 minutes.

-> 5/6 of 60 minutes
5/6*60
=50

So, 50 minutes

-> 1/2 of 60 minutes
1/2*60
=30

So, 30 minutes

-> 2/3 of 60 minutes
2/3*60
=40

So, 40 minutes.

Hope this helps. If you have any questions, please put them in the comments below.

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Please tell me correct and

choli [55]

Answer:

$\frac{1}{4}$ or $0.25$ (they're the same)

Step-by-step explanation:

First Part:

$4^{3} = 64$
$8^{2} = 64$
$2 = 2$
Multiply them together: 64 × 64 × 2 = 8192

Second Part:

$2^{7} = 128$
$16^{2} = 256$
Multiply them together: 128 × 256 = 32768

Wrap it all up:

8192 ÷ 32768 = 0.25 = 1/4

I hope this helps!

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2 years ago

Complete the point slope of the line through (-5,4) and (1,6)

Vesnalui [34]

Answer:

Step-by-step explanation:

The slope is given by change in the ordinate divided by change in the abscissa.= Y2-Y1/X2-X1

=6-4/1+5= 2/6= 1/3

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2 years ago

Read 2 more answers

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S_A_V [24]

Answer:

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Step-by-step explanation:

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2 years ago

Suppose a population has a mean of 7 for some characteristic of interest and a standard deviation of 9.6. A sample is drawn from

valkas [14]

Answer: A. 1.2

Step-by-step explanation:

Given : Sample size : n= 64

Standard deviation: $\sigma=9.6$

The formula to find the standard error of mean is given by :-

$S.E.=\dfrac{\sigma}{\sqrt{n}}\\\\\Rightarrow\ S.E.=\dfrac{9.6}{\sqrt{64}}\\\\\Rightarrow\ S.E.=\dfrac{9.6}{8}=1.2$

Therefore, the standard error of the mean= 1.2

Hence, A is the right option.

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2 years ago

A business has two loans totaling $50,000. One loan has a rate of 8% and the other has a rate of 12%. This year, the business ex

Debora [2.8K]

Answer:

the 8% loan has a principal of $37500

the 12% loan has a principal of $12500

Step-by-step explanation:

Let's start by writing the general equation for the interest hwre I is the interest, P is the principal (in our case would be loan amounts), "r" is the interest rate in decimal form (in our case one would be 0.12, and the other one 0.08), and t is the time in years (in our case 1 year).

$I=P*r*t$

Then we write the interest equation coming from each loan at the end of this year (we call I1 the interest coming from the 12% loan and I2 the interest coming from the 8% one). Since we don't know the loan amounts (in fact those are what we need to find) we will name one "x" and the other "y":

$I=P*r*t\\I1=x * 0.12*1\\I2=y*0.08*1$

Next, we add these last two equations term by term, and replace the addition of both interests by $4500 as given in the information:

$I1=x * 0.12*1\\I2=y*0.08*1\\I1+I2 = 0.12x+0.08y\\4500=0.12x+0.08y$

This is our first equation in the variables x and y which are our unknowns.

Now we generate the second equation on x and y by writing in agebraic terms the other piece of information we have: "the total of the two loans is $50000. That is the addition of the principals x and y should equal $50000:

$x+y=50000$

We solve for y in this last equation and replace its form in terms of x in the equation of the interest, and solve for the unknown x:

$y=50000-x\\4500 = 0.12x +0.08 y\\4500=0.12x+0.08(50000-x)\\4500=0.12x+4000-0.08x\\4500=0.12x-0.08x+4000\\4500=0.04x+4000\\4500-4000=0.04x\\500=0.04x\\x=\frac{500}{0.04} =12500$

Therefore the amount of the loan at 12% is $12500

Now to find the amount of the second loan "y" we use the equation for the totals of the loans:

$x+y=50000\\12500+y=50000\\y=50000-12500=37500$

Therefore, the loan at 8% is $37500

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2 years ago