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3 years ago

Plz help meeee !!!!!

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

7 0

I say that it is A because I did this did this before

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Solve the initial value problems.

slavikrds [6]

Both equations are linear, so I'll use the integrating factor method.

The first ODE

$xy' + (x+1)y = 0 \implies y' + \dfrac{x+1}x y = 0$

has integrating factor

$\exp\left(\displaystyle \int\frac{x+1}x \, dx\right) =\exp\left(x+\ln(x)\right) = xe^x$

In the original equation, multiply both sides by eˣ :

$xe^x y' + (x+1) e^x y = 0$

Observe that

d/dx [xeˣ] = eˣ + xeˣ = (x + 1) eˣ

so that the left side is the derivative of a product, namely

$\left(xe^xy\right)' = 0$

Integrate both sides with respect to x :

$\displaystyle \int \left(xe^xy\right)' \, dx = \int 0 \, dx$

$xe^xy = C$

Solve for y :

$y = \dfrac{C}{xe^x}$

Use the given initial condition to solve for C. When x = 1, y = 2, so

$2 = \dfrac{C}{1\cdot e^1} \implies C = 2e$

Then the particular solution is

$\boxed{y = \dfrac{2e}{xe^x} = \dfrac{2e^{1-x}}x}$

The second ODE

$(1+x^2)y' - 2xy = 0 \implies y' - \dfrac{2x}{1+x^2} y = 0$

has integrating factor

$\exp\left(\displaystyle \int -\frac{2x}{1+x^2} \, dx\right) = \exp\left(-\ln(1+x^2)\right) = \dfrac1{1+x^2}$

Multiply both sides of the equation by 1/(1 + x²) :

$\dfrac1{1+x^2} y' - \dfrac{2x}{(1+x^2)^2} y = 0$

and observe that

d/dx[1/(1 + x²)] = -2x/(1 + x²)²

Then

$\left(\dfrac1{1+x^2}y\right)' = 0$

$\dfrac1{1+x^2}y = C$

$y = C(1 + x^2)$

When x = 0, y = 3, so

$3 = C(1+0^2) \implies C=3$

$\implies \boxed{y = 3(1 + x^2) = 3 + 3x^2}$

7 0

2 years ago

Evaluate 4 − 0 . 2 5 g + 0 . 5 h 4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g = 1 0 g=10g, equals, 10 and

abruzzese [7]

Not sure about the weird echo in the question but I think we're being ask to evaluate

4 - 0.25g + 0.5h

when g=10, h=5

That's

4 - 0.25(10) + 0.5(5) = 4 - 2.5 + 2.5 = 4

Answer: 4

6 0

3 years ago

Read 2 more answers

What is the square root of 325 rounded to two decimal places?

hammer [34]

The square root of 325 is 18.03

7 0

4 years ago

Which of the statements below is true for the following set of numbers? 42, 15, 36, 51, 65, 28

Llana [10]

Answer:

List the options so we can help you out here.

Thank you in advance.

4 0

3 years ago

What is 10 times 10 with an exponent of negative 1 times negative 2 with an exponent of negative 5?

abruzzese [7]

10*10^-1 * -2^-5 =
10 * .1 * -0.03125 =
-.03125

3 0

3 years ago