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Tasya [4]
3 years ago
10

Billy says that he can add 23 and 40 without regrouping is Bill correct how do you know

Mathematics
1 answer:
bija089 [108]3 years ago
6 0
Yes he is correct because if you do the algorithm, 0+3=3 and 20+40=60 and 60+3=63. There is no regrouping needed.
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A restaurant offers three sizes of coffee and four differerſt types of coffee.
Kruka [31]
<h3>Answer:  864</h3>

=======================================================

Work Shown:

There are,

  • 3 sizes of coffee
  • 4 types of coffee
  • 2 choices for cream (you pick it or you leave it out)
  • 2 choices for sugar (same idea as the cream)

This means there are 3*4*2*2 = 12*4 = 48 different coffees. We'll use this value later, so let A = 48.

There are 6 bagel options. Also, there are 3 choices in terms of if you order the bagel plain, with butter, or with cream cheese. This leads to 6*3 = 18 different ways to order a bagel. Let B = 18.

Multiply the values of A and B to get the final answer

A*B = 48*18 = 864

There are 864 ways to order a coffee and bagel at this restaurant.

--------------

If you're curious why you multiply the values out, consider this smaller example.

Let's say you had 3 choices of coffee and 2 choices for a bagel. Form a table with 3 rows and 2 columns. Place the different coffee choices along the left to form each row. Along the top, we'll have the two different bagel choices (one for each column).

This 3 by 2 table leads to 3*2 = 6 individual table cells inside. Each cell in the table represents a coffee+bagel combo. This idea is applied to the section above, but we have a lot more options.

3 0
2 years ago
∠45° is complementary to which of the following angles?
mixas84 [53]

Answer:

45°

Step-by-step explanation:

<em>complem</em><em>entary</em><em> </em><em>angl</em><em>es</em><em> </em><em>add</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>9</em><em>0</em><em>°</em><em> </em><em>so</em><em> </em><em>it's </em><em>9</em><em>0</em><em>-</em><em>4</em><em>5</em>

4 0
2 years ago
Find the number of roots for each equation.<br> 5. 5x4 + 12x3 – x2 + 3x + 5 = 0
pav-90 [236]

Answer:

The number of roots for  equation 5x^4 + 12x^3 – x^2 + 3x + 5 = 0 is 4 .

Step-by-step explanation:

Here, the given function polynomial is :

P(x) : 5x^4 + 12x^3 – x^2 + 3x + 5 = 0

The Fundamental Theorem of Algebra says that a polynomial of degree n will have exactly n roots (counting multiplicity).

Now here, the degree if the polynomial is 4 (highest power of variable x).

So, according to the Fundamental Theorem, the given polynomial can have AT MOST 4 roots, counting Multiplicity.

Hence,  the number of roots for  equation 5x^4 + 12x^3 – x^2 + 3x + 5 = 0 is 4 .

7 0
3 years ago
solve the linear equation 29 - 3x = 5x + 5 state the property that justifies your step and why you chose it
Debora [2.8K]

Answer:

x=3

Step-by-step explanation:

29-3x=5x+5

29=5x+5+3x

29=8x+5

29-5=8x

24÷8=x

3=x

6 0
3 years ago
Solve and graph the compound inequality:<br> 5C + 3 &lt; 28 and -4C – 2 14
LekaFEV [45]

5 C + 3 < 28 a - 4 C - 214

a>9c +31

------------

28. 4

C >28a-21

------

9

4 0
3 years ago
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