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2 years ago

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Which two operations are needed to wrte the expression that represents Fournes heerence of a number and three? mult cation and s

ubtraction Komision and subtraction Cmu tip cation and addition division and addition

1 answer:

balu736 [363]2 years ago

7 0

Answer:

CMU+the curcumin of three is Fournes

Step-by-step explanation:

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A manufacturing process outputs parts having a normal distribution with a mean of 30 cm and standard deviation of 2 cm. From a p

Arisa [49]

Answer:

68% of the sample can be expected to fall between 28 and 32 cm

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 30

Standard deviation = 2

What proportion of the sample can be expected to fall between 28 and 32 cm

28 = 30-2

28 is one standard deviation below the mean

32 = 30 + 2

32 is one standard deviation above the mean

By the Empirical Rule, 68% of the sample can be expected to fall between 28 and 32 cm

7 0

3 years ago

A sample of n = 5 scores has a mean of m = 8. one new score is added to the sample and the new mean is calculated to be m = 9. w

Yuri [45]

If the 5 scores have a mean of 8, then their total sum would be 8*5 = 40

Now if one score if added (let's call this score x), there are 6 scores and the mean changes to 9, thus:
(40 + x)/6 = 9
40 + x = 54
x = 14

6 0

3 years ago

Read 2 more answers

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

So

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

2 years ago

Solve the right triangle. Round decimal answers to the nearest tenth. find the sides and angles

babymother [125]

Answer:

b = 12.6

Step-by-step explanation:

a*2 + b*2 = c*2

6*2 + b*2 = 14*2

36 + b*2 = 196

Subtract 36 from both sides

36 + b*2 = 196

-36 -36

b*2 = 160

Find the square root of both

b = 12.64911064 or 12.6

4 0

3 years ago

un rectangulo tiene 28 cm de perimetro y unos de sus lados mide 4 cm ¿cuantos cuadrados de 2 cm por lado se mecesitan para armar

seraphim [82]

Answer:

10 cuadrados

Step-by-step explanation:

Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.

28 - 8 = 20cm

20cm / 2cm = 10cm

Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo

10cm * 4cm = 40 $cm^{2}$

el cuadrado de 2cm tendra un area de

2cm * 2cm = 4 $cm^{2}$

Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo

40 $cm^{2}$ / 4 $cm^{2}$ = 10 cuadrados

3 0

2 years ago