To work out the average, you add all the terms and divide that by the number of terms there are.
64 + 63 = 127
127 ÷ 2 = 63.5
The answer is 63.5.
However, because these are only two consecutive integers, you just add 0.5 to find the average. e.g: average of 2 and 3 = 2.5, average of 3 + 4 = 3.5, average of 6 + 7 = 6.5 etc... Remember, this only works if there are only two integers and they are consecutive.
Answer:
D - 192
Step-by-step explanation:
So the solve this, lets use the formula for area of a triangle:
b*h / 2 = A
b is the base, h is the height.
In this case, our base is 32, and our height is unknown.
To find it we must use pythagreons theorm:

a is half of the base in this case, since tecnically this iscoceles traingle(2 same sides) cut in half is 2 right triangles.
32/2 = 16
b is the unknown, and C is the hypotenuse(longest length) which is 20:




So we know b, whihc is our height, is 12.
Plugging this in:
32*12 / 2 = A
384 / 2 = A
192 = A
So the area of the triangle is 192.
Hope this helps!
Answer:
The probability the man was hit by a Blue Cab taxi is 41%.
Step-by-step explanation:
In terms of bayesian probability, we have to calculate P(B|Wr), or, given the witness saw the right colour, the taxi is from the Blue Cab company.
According to Bayes
P(B|Wr) = P(Wr|B)*P(B)/P(Wr)
P(Wr|B) = 0,8
P(B) = 0.15
To calculate P(Wr), or the probability of the witness of guessing right, we have to consider the two possibilities:
1) The taxi is from Blue Cab (B) and the witness is right (Wr).
2) The taxi is from Green Cab (G) and the witness is wrong (Ww).
The total probality of guessing right is
P(B)*P(Wr) + P(G)*P(Ww) = 0.15*0.8 + 0.85*0.2 = 0.29
So we can calculate:
P(B|Wr) = P(Wr|B)*P(B)/P(Wr) = 0.8*0.15/0.29 = 0.41
The probability the man was hit by a Blue Cab taxi is 41%.
Answer:
one is smaller then the other i think thats it
Step-by-step explanation:
Answer:
Graph (1)
Step-by-step explanation:
Given equation of the graph is,
y = 20(1.25)ˣ
Table for the input - output values of the function,
x -2 -1 0
y 12.8 16 20
These points lie on curve (1).
Therefore, curve (1) will be the graph represented by the equation.