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natulia [17]
3 years ago
12

Can you factor the common factor out of this problem? 3p+12q-15q^2r^2

Mathematics
2 answers:
motikmotik3 years ago
6 0
Greatest common factor is 3
ioda3 years ago
5 0
The answer after being factored is, -3( 5q^{2}  r^{2} -p-4q)

When we are factoring, all we are doing is finding a GCF and taking it from the expression and dividing it into every term. Let's break our expression into parts first

3p

12q

-15q^{2}  r^{2}

Now, each number is divisible by 3, but since our biggest number is a negative, we will make our GCF -3 instead of 3. So let's divide each part by -3.

3p / -3 =-p

12q/-3=-4q

-15q ^{2}  r^{2} /-3=5q^{2}  r^{2}

Now let's put it together in an expression:

5q^{2}  r^{2} -p-4q

When we factor we always put our factored expression in parenthesis with the term the expression was factored by on the outside like so:


-3(5q^{2} r^{2} -p-4q)

Thank you for the question I hope this helped! Have an amazing day! :D
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Answer:

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Step-by-step explanation:

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Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: m= \frac{y_{2}-y_{1}}{x_2-x_1}

Rate of change of a:
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Rate of change of b:
Here the end points are (0,0) and (2,2)
m= \frac{2-0}{2-0}
m= \frac{2}{2}
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The average rate of change of the function b over the interval [0,2] is 1

Rate of change of c:
Here the end points are (0,-1) and (2,0)
m= \frac{0-(-1)}{2-0}
m= \frac{1}{2}
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The average rate of change of the function c over the interval [0,2] is 0.5

Rate of change of d:
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We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>
4 0
3 years ago
A rose garden is designed by joining a rectangle and a semicircle, as shown below. The rectangle is
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The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of
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Answer:

180.4~cm^2

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

A=2\pi rh

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

A=2\pi rh+2\pi r^2

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

Now we calculate the side area of the can:

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We need to add the 0.8 cm overlap to the total area already calculated. This overlap has 0.8 cm of width and 8.5 cm of height, so this overlap area is:

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The total area of the label is:

A=173.6~cm^2+6.8~cm^2=180.4~cm^2

The area of the label is \mathbf{180.4~cm^2}

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