if x≥0 then |x|=x
if x<0 then |x|=-x
1) for x≥0
2) for x<0
The answer is:
How many solutions exist for the given equation? 3x + 13 = 3(x + 6) + 1
2 answers:
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if x≥0 then |x|=x
if x<0 then |x|=-x
1) for x≥0
2) for x<0
The answer is:
