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vampirchik [111]
3 years ago
8

CotA + tanA= secAcosecA

Mathematics
2 answers:
gregori [183]3 years ago
8 0

Step-by-step explanation:

cotA + tanA

= cosA / sinA+ sinA/ cosA

= cos2A + sin2A / sinA* cosA

= 1 / sinA* cosA

=1/ sinA * 1/ cosA

= cosecA *secA

=secAcosecA

Snezhnost [94]3 years ago
8 0

\frac{cos^2A + sin^2A}{sinAcosA}Answer:

Step-by-step explanation:

cotA + tanA = secAcosecA

LHS=cotA + tanA

=\frac{cosA}{sinA} + \frac{sinA}{cosA}

take lcm of the denominator

=\frac{cosA*cosA + sinA*sinA}{sinAcosA}(COS^2A + sin^2A =1)

=\frac{1}{sinAcosA}

=1/sinA * 1/cosA

=cosecA*secA

=secAcosecA

therefore LHS=RHS

hence proved.

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