Answer:
Step-by-step explanation:
Alright, lets get started.
Please refer the diagram I have attached.
The given is a right triangle.
Two sides are given as 120 and 122.
120 is adjacent
122 is hypotenuse
Using SOH CAH TOA
taking cos inverse on both sides
Using calculator
C = 10.39 : Answer
Hope it will help :)
Numbers are x and y
x is 5 more than y
x=5+y
product is -3
xy=-3
solve
sub 5+y for x since x=5+y
(5+y)y=-3
5y+y^2=-3
add 3 to both sides
y^2+5y+3=0
use quadratic formula where
ay^2+by+c=0
y=
a=1
b=5
c=3
y=
y=
y=
y=
or
the second number is 5 more or 10/2 more
add 10/2 to each
x=
or
the numbers are
and
or
and
aprox
the numbers are
-0.697224 and 5.967224 or
-4.302775 and 0.697224
Answer:
1. k(x) = (3g + 5h)(x) = -24x+40
2. k(x) = (h - g)(x) = 0
3. k(x) = (g + h)(x) = -6x+10
4. k(x) = (5g + 3h)(x) = -24x+40
5. k(x) = (3h - 5g)(x) = 6x-10
6. k(x) = (5h - 3g)(x) = 10-6x
Step-by-step explanation:
Given
h(x) = 5 - 3x
and
g(x) = -3 x + 5
1. k(x) = (3g + 5h)(x)
3*g(x) = 3(-3 x + 5)
=> -9x+15
5*h(x) = 5(5 - 3x)
=>25-15x
(3g + 5h)(x)=3*g(x)+5*h(x)
= -9x+15+25-15x
=-9x-15x+15+25
=-24x+40
2. k(x) = (h - g)(x)
(h - g)(x) = h(x) - g(x)
= 5 - 3x -(-3 x + 5)
=5-3x+3x-5
= 0
3. k(x) = (g + h)(x)
(g+h)x = g(x) + h(x)
= -3 x + 5 + 5 - 3x
= -6x+10
4. k(x) = (5g + 3h)(x)
5*g(x) = 5(-3 x + 5)
=-15x+25
3*h(x) = 3(5 - 3x)
=15-9x
(5g + 3h)(x) = 5*g(x) + 3*h(x)
= -15x+25+15-9x
= -15x-9x+25+15
=-24x+40
5. k(x) = (3h - 5g)(x)
(3h - 5g)(x) = 3*h(x)-5*g(x)
=15-9x-(-15x+25)
=15-9x+15x-25
=-9x+15x+15-25
=6x-10
6. k(x) = (5h - 3g)(x)
5*h(x)-3*g(x) = 25-15x - (-9x+15)
= 25-15x+9x-15
= 25-15-15x+9x
=10-6x
Answer:
10=y/11-13
We move all terms to the left:
-10-(y/11-13)=0
-y/11+13-10=0
We multiply all the terms by the denominator
-y+13*11-10*11=0
We add all the numbers together, and all the variables
-1y+33=0
We move all terms containing y to the left, all other terms to the right
-y=-33
y=-33/-1
y=+33
Step-by-step explanation:
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