Can u pls help me with this question asap

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the women and men who smoke respectively. The population proportion of women and men who smoke would be p1 and p2 respectively.

p1 - p2 = difference in the proportion of women and men who smoke.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 > p2

p1 - p2 > 0

it is a right tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For women

x1 = 14

n1 = 110

p1 = 14/110 = 0.13

For men,

x2 = 7

n2 = 95

p2 = 7/95 = 0.07

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (14 + 7)/(110 + 95) = 0.1

1 - pc = 1 - 0.1 = 0.9

z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.13 - 0.07)/√(0.1)(0.9)(1/110 + 1/95)

z = 1.47

From the options given, the test statistic is

e. none of these is correct.

Since it is a right tailed test, we will look at the area to the right of z = 1.47. The p value would be

p value = 1 - 0.9292 = 0.078

Since alpha, 0.005 < than the p value, 0.078, then we would fail to reject the null hypothesis. Therefore, the data does not indicate that the proportion of women who smoke cigarettes is higher than the proportion of men who do at α=.005

8 0

3 years ago

Of the three different types of horses on a ranch, 1/4 are Arabians, 2/5 are Thoroughbreds, and the rest are Morgan's. What frac

mars1129 [50]

Answer:

The fraction of horses that are Morgan's=17/20

Step-by-step explanation:

Step 1: Determine fraction for each breed

Arabians=1/4

Thoroughbreds=2/5

Morgan's=unknown

Step 2: Express each breed as a fraction of the total

Number of Arabians=fraction of Arabians×total number of horses

Let total number of horses be x

Arabians=(1/4)×x=1/4 x

Thoroughbreds=(2/5)×x=2/5 x

Morgans's=m

Step 3: Calculate fraction of Morgans

Total number of horses=Arabians+Thoroughbreds+Morgans

x=(1/4)x+(2/5)x+m

solve for m;

m=x-(1/4)x-(2/5)x

m=x-3/20x

m=17/20 x

The fraction of horses that are Morgan's=17/20

6 0

4 years ago

Could someone help me with B

pishuonlain [190]

Answer:

$a_n = 12 - 3n$

Step-by-step explanation:

The first term is 9.

Term 1 is 9.

Term 2 is 9 - 3.

Term 3 is 9 - 2(3).

Term 4 is 9 - 3(3).

Term 5 is 9 - 4(5)

Notice the pattern in terms 3 through 5. For each term, subtract 1 less than the term number multiplied by 3 from 9.

For term n, you subtract 1 less than n times 3 from 9.

The nth term is 9 - (n - 1) * 3

$a_n = 9 - (n - 1) \times 3$

Now we simplify the expression on the right side.

$a_n = 9 - 3(n - 1)$

$a_n = 9 - 3n + 3$

The expression for the nth term is

$a_n = 12 - 3n$

Let's see if it works.

n = 1

$a_n = 12 - 3(1) = 12 - 3 = 9$

n = 2

$a_n = 12 - 3(2) = 12 - 6 = 6$

n = 3

$a_n = 12 - 3(3) = 12 - 9 = 3$

n = 4

$a_n = 12 - 3(4) = 12 - 12 = 0$

n = 5

$a_n = 12 - 3(5) = 12 - 15 = -3$

n = 6

$a_n = 12 - 3(6) = 12 - 18 = -6$

As you can see, following this rule fro the nth term, we got the same first siz terms you got above. Our answer is correct.

Answer: $a_n = 12 - 3n$

4 0

3 years ago

Can u pls help me with this question asap​

Can u pls help me with this question asap