Answer:
6s + 2s - 3s - 6:
5s-6
10t - 4t -6 + 5t:
11t-6
18r + 18r + 9r - 3r:
42r
20 - 4q + 40r - 16:
-4q+40r+4
17st - 16s + t:
17st-16s+t
. 101+101x - x:
101+100x
16a2 - 14a + a2 - 3a:
14 ato the power of 2- 17a
14t + 14t + t:
29t
r + s + rs + s + rs + s:
r+2rs+3s
54 pt - 3p + 4t - 3pt:
51pt-3p+4t
i dont know 11
101c - 5c +4c:
100c
12q - 4 + 10q - 4q +9:
18q+5
21k - 20k + 3k:
4k
181x + 91x - 23x:
249x
Step-by-step explanation:
Number 2 is 84.13
number 4 is 56
Well, I'm not completely sure, because I don't know the formal definition
of "corner" in this work. It may not be how I picture a 'corner'.
Here's what I can tell you about the choices:
A). (0, 8)
This is definitely a corner of the feasible region.
It's the point where the first and third constraints cross.
So it's not the answer.
B). (3.5, 0)
This is ON the boundary line between the feasible and non-feasible
regions. But it's not a point where two of the constraints cross, so
to me, it's not what I would call a 'corner'.
C). (8, 0)
Definitely not a corner, no matter how you define a 'corner'.
This point is deep inside the non-feasible zone, and it doesn't
touch any point in the feasible zone.
So tome, this looks like probably the best answer.
D). (5, 3)
This is definitely a corner. It's the point of intersection (the solution)
of the two equations that are the first two constraints.
The feasible region is a triangle.
The three vertices of the triangle are (0,8) (choice-A),
(0,-7) (not a choice), and (5,3) (choice-D) .
region is a triangle
Answer:
Move all terms that don't have "y
" in it to the right side and solve.
y
=−
17
/5
+
4
x
/5
Step-by-step explanation:
Answer:
C) (x,y) → (x,y+6)
Step-by-step explanation:
As the x value stays the same after the transformation, we know that there can be no changes to the value x, automatically limiting the options to answer C.
The mathematical way to find the value y is changed by would be by setting up a small equation as follows:
, where n is some number that the y value is altered by.
Solving for n gives the value 6, proving that the translation must add 6 to the y value.