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Andrew [12]
3 years ago
10

Suppose A and B are two matrices with the same dimensions. Explain how to find A + B and B - B.

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0
A+B: the matrix with same dimension a A and B, the element in row i and column j is:  Aij+Bij

Same for A-B, but with Aij-Bij
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describe the horizontal and/or vertical shifts used to transform the equation y=|x| to the equation y=|x|+4
netineya [11]
It will move 4 to the right horizontally
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8 and 4 / 9 divided by 2 and 1 / 9<br><br><br> 10 points<br><br> Please show work
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Dydyeufogofififudugjdid7fogo

7 0
3 years ago
There are a total of 15 dimes and quarters in a covered cup. The value of all 15 coins totals 2.85
QveST [7]

Answer:

There are 6 dimes and 9 quarters.

Step-by-step explanation:

Represent the number of dimes and the number of quarters by d and q.

Then d + q = 15, or q = 15 - d.

Also, ($0.25)q + ($0.10)d = $2.85, or 5q + 2d = 57.

Substituding 15 - d for q, we get 5(15 - d) + 2d = 57, or

75 - 5d + 2d = 57, or

75 - 3d = 57, or

3d = 18.  Thus, there are 6 dimes.  Since q = 15 - d, q = 15 - 6 = 9.

There are 6 dimes and 9 quarters.

6 0
3 years ago
What is the equivalent of <br>2/3x -9 - 2x + 2 = 1 after combining like terms?​
elena-s [515]

Answer:

5

Step-by-step explanation:

5 0
3 years ago
Solve the equation 6w2 – 7w – 20 = 0.
azamat

For this case we have the following quadratic equation:

6w ^ 2-7w-20 = 0

Where:

a = 6\\b = -7\\c = -20

Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

Answer:

w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}

7 0
3 years ago
Read 2 more answers
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