A is the answer i hope this helsp
Answer:
231
Step-by-step explanation:
=
42÷2= 21
9×21= 189
189 students total
42 6th graders
Answer:
1: D
2: B
3: y=-4x+22
4: y=-8x+26
Step-by-step explanation:
1: Parallel lines have the same slope, and the only one with a slope of 3x is D
2: Perpendicular lines have an opposite slope, so a line with a slope of -1/2 would be 2, so you just flip the number and add or take away a negative sign, depending on the original slope
3: Like I said before, perpendicular lines have an opposite slope, so the slope would be -4. After you've figured that out, you just plug in the numbers given to you (and remember, x is first, y is last)
Plug in: 6=-4(4)+b
You would then solve for b.
6=-16+b
22=b
Then plug that into y=mx+b, with m being the slope (-4) and b being the y intercept (22)
4: The process for finding parallel and perpendicular lines is very similar, except you don't have to change the slope.
Plug in: 10=-8(2)-b
10=-16+b
26=b
Again, plug that into the equation y=mx+b
Hope I could be of help! Sorry if it doesn't make sense, this is my first time on this website.
Answer:
18.37 is the answer so it should be 18.4
Step-by-step explanation:
Answer:
32
Step-by-step explanation:
1. If you take 12 balls, 9 could be yellow and 3 could be red. We want at least 12 of the same color, so 30 balls isn't a good minimum
2. If you take 30 balls, 9 could be yellow, 10 could be red and 11 could be green. We want at least 12 of the same color, so 30 balls isn't a good minimum.
3. If you take 31 balls, 9 could be yellow, 11 could be red and 11 could be green. We want at least 12 of the same color, so 31 balls isn't a good minimum.
4. If you take 32 balls, 9 could be yellow, 11 could be red and 12 could be green or 9 could be yellow, 12 could be red and 11 could be green or 7 could be yellow, 13 could be red and 12 could be green or 9 could be yellow, 11 could be red and 12 could be green.
We want at least 12 of the same color, and we have it from the different samples of the 4th trial.
So, 32 balls is the minimum number of balls
