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ad-work [718]
3 years ago
13

In a circle with radius 2.1, an angle intercepts an arc of length 21.2. Find the angle in

Mathematics
1 answer:
inessss [21]3 years ago
6 0

Given:

Radius of a circle = 2.1 units

Arc length = 21.2 units

To find:

The central angle in radians to the nearest 10th.

Solution:

We know that the intercepted arc length is

s=r\theta

Where, s is the arc length, r is the radius and \theta is the central angle in radians.

Putting the given values, we get

21.2=2.1\theta

\dfrac{21.2}{2.1}=\theta

10.095238=\theta

\theta\approx 10.1

Therefore, the angle in radians is 10.1.

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Rebecca's dog runs with an initial speed of 1.5m/s on a waxed floor. It slides to a stop within an acceleration of -.25 m/s/s. H
yanalaym [24]
The correct  answer would be : 1.75
8 0
3 years ago
Find the measure of angle C of a triangle ABC, if: d m∠A = 60°+α, m∠B = 60°−α
snow_lady [41]

Answer:

m∠C  =  60°

Step-by-step explanation:

we know that sum of angles of a traingle is 18 degrees.

given

m∠A = 60°+α,

m∠B = 60°−α

we have to find  m∠C

m∠A + m∠B +  m∠C = 180

60°+α +  60° - α +m∠C = 180

+α and -α gets cancelled

120°+m∠C = 180

=> m∠C  =  180° -  120° =  60°

Thus, measure of angle c is  60°.

8 0
3 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, -5). Write the equati
amid [387]
In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form
f(x) = a(x - x_1)(x-x_2)(x-x_3)

As we know zeros are that point where we will get value of function equal to zero. So it is basically in form (x_n , 0)

SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say x_1 = 2 , x_2 = 3 , x_3 = 5

So required equation is
f(x) = a (x-2)(x-3)(x-5)
              = a[(x^2 - 2x - 3x + 6)(x-5)]
              = a[(x^2 - 5x+6)(x-5)]
              = a(x^3 - 5x^2 + 6x- 5x^2 + 25x - 30)
              = a(x^3 - 10x^2+31x-30)
Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5
-5= a (0-0+0 - 30)
-5 = -30a
a =  \frac{-5}{-30} =  \frac{1}{6}
So required equation of cubic polynomial is
f(x) =  \frac{1}{6}(x^3 -10x^2+31x-30)

For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
4 0
3 years ago
Read 2 more answers
Need help and will be giving Brainliest
Katena32 [7]

Answer:

x-intercept (s):

For this case h (x) = 0

x2 - 2x - 8 = 0

(x-4) * (x + 2) = 0

x1 = 4

x2 = -2

y-intercept:

For this case x = 0

h (0) = (0)2 - 2 (0) - 8

h (0) = - 8

vertex:

We derive the equation:

h '(x) = x2 - 2x - 8

h (x) = 2x - 2

We match zero:

2x-2 = 0

x = 2/2

x = 1

We evaluate the function for x = 1

h (1) = (1)2 - 2 (1) - 8

h (1) = 1 - 2 - 8

h (1) = -9

The vertex is:

(1, -9)

axis of symmetry of the function:

x = 1

Step-by-step explanation:

hope it helps

6 0
3 years ago
Alina drew a model of a square pyramid. The dimensions of the model are shown in the diagram. pls don't answer with links
Romashka [77]

Answer:

C

Step-by-step explanation:

Volume of a pyramid = 1/3 base area * height

                                   = 1/3 (8 * 10)(12)

6 0
2 years ago
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