All categories

3 years ago

Can you please help me with this

Mathematics

1 answer:

Vitek1552 [10]3 years ago

5 0

Answer:

log9

Step-by-step explanation:

Using the rules of logarithms

logx + logy = log(xy)

logx - logy = log( $\frac{x}{y}$ )

log $x^{n}$ ⇔ nlogx

Given

2(log18- log3) + $\frac{1}{2}$ log $\frac{1}{16}$

= 2(log( $\frac{18}{3}$ ) ) + log $(\frac{1}{16}) ^{\frac{1}{2} }$

= 2log6 + log $\frac{1}{4}$

= log6² + log $\frac{1}{4}$

= log36 + log $\frac{1}{4}$

= log( 36 × $\frac{1}{4}$ )

= log9

You might be interested in

(23 + ) + 19 = 23 + ( + 19)

Tpy6a [65]

I think it should be 42

6 0

3 years ago

Which definition best describes vertical angles?

Artyom0805 [142]

Answer:

B is the answer

Step-by-step explanation:

Vertical angles are pair angles formed when two lines intersect. Vertical angles are sometimes referred to as vertically opposite angles because the angles are opposite to each other

4 0

3 years ago

Which function best models the data in the graph?

Alex777 [14]

I g=2.04x
O y=10.2/x

8 0

3 years ago

Read 2 more answers

Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$