Do this by setting up a form of system of equations.
a + s = 369
2a = s
Let’s use substitution to find the number of adult tickets!
a + 2a = 369
3a = 369
a = 123
So, there were 123 adult tickets sold!
Answer:
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:
Answer:
√16×81 = 4×9 or √1296 = 36
√16×√81 = 4×9 = 36
Step-by-step explanation:
√81×16
We simplify 81 and 16 by prime factorisation (expressing a number as a product of its prime factors).
√81 = √3×3×3×3 = √9×9 = √9² = 9
√16 = √2×2×2×2 = √4×4 = √4² = 4
Answer: the first box put 2
The second box put 3
Step-by-step explanation:
i will explain in the comments below
C and E. I hope this helps :)