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Aleksandr [31]
3 years ago
14

there are 500 tickets for sale in A raffle. tickets cost $3 each, or $20 for A book of 10. All 500 tickets were sold, and $1350

was raised. How many books of 10 tickets were sold?​
Mathematics
2 answers:
KATRIN_1 [288]3 years ago
5 0

Answer:

67 books of tickets

Step-by-step explanation:

-To get this, you just divide 1,350 by 20, and you will get 67!

Marat540 [252]3 years ago
5 0

Answer:

15 booklets of 10 tickets each were sold.  

Step-by-step explanation:

We are given the following information:

Let x be the number of single tickets sold and y be the number of booklets sold.

Each booklet consist of 10 tickets.

There are total of 500 tickets.

Thus, it can be represented by the equation:

x + 10y =500

The cost of single ticket = $3

Cost of booklet = $20

Total money raised = $1,350

This, can be represented in the equation:

3x + 20y = 1350

Now, we have obtained two equation in two variable. Solving these equations, we get:

2x + 20y = 1000\\3x + 20y = 1350\\x = 350\\y = 15

Thus, 15 booklets of 10 tickets each were sold.

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Write the equation of the line perpendicular to 2x+3y=9 that passes through (-2,5). Write your answer in slope-intercept form. S
Harman [31]
ANSWER

y =  \frac{3}{2} x + 8



EXPLANATION

The line given to us has equation,

2x + 3y = 9

We need to write this equation in the slope intercept form to obtain,


3y =  - 2x + 9



\Rightarrow \: y =  -  \frac{2}{3}x + 3


The slope of this line is

m_1 =  -  \frac{2}{3}
Let the slope of the perpendicular line be

m_2

Then
m_1 \times m_2 =  - 1


-  \frac{2}{3} m_2=  - 1

This implies that,

m_2 =  - 1 \times  -  \frac{3}{2}


m_2 =  \frac{3}{2}



Let the equation of the perpendicular line be,

y = mx + b

We substitute the slope to get,


y =  \frac{3}{2} x + b

Since this line passes through
(-2,5)
it must satisfy its equation.


This means that,

5=  \frac{3}{2} ( - 2)+ b


5 =  - 3 + b



5 + 3 = b


b = 8

Wherefore the slope-intercept form is

y =  \frac{3}{2} x + 8
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