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lisabon 2012 [21]
4 years ago
7

Give an example of a coefficient in math

Mathematics
1 answer:
RoseWind [281]4 years ago
4 0
In the equation, 5x+3, 5 is the (numerical) coefficient
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A parabola can be drawn given a focus of (6,0) and a directrix of y = -6. Write the
VLD [36.1K]

Answer:

Equation of the parabola: 12y+36=(x-6)^2 or y=\frac{x^2}{12} -x

Vertex form: y=\frac{1}{12} (x-6)^2-3

Intercept form: y=\frac{x}{12} (x-12)

Step-by-step explanation: hope this helps please give brainlieat!

7 0
3 years ago
Read 2 more answers
A corporate team-building event costs $13, plus an additional $6 per attendee. How many
andrew-mc [135]

Answer:

 12

Step-by-step explanation:

The cost for n attendees will be ...

 cost = 2 + 2n

We want the cost to be, at most, 26, so we have ...

 26 ≥ 2 +2n

Dividing by 2 gives ...

 13 ≥ 1 + n

And subtracting 1, we find the answer:

 12 ≥ n

At most, there can be 12 attendees.

5 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
A wire is first bent into the shape of a rectangle with width 5in and length 13in. Then the wire is unbent and reshaped into a t
MAXImum [283]
Total length of the wire = 2*13 + 2*5 = 26 + 10 = 36 in.

so length of each side of the triangle would be 36/3  = 12 ins.
8 0
3 years ago
A fair coin is tossed 14 times, what is the probability of exactly 6 heads
Mrrafil [7]

Answer:

42.85% or 6/14

Step-by-step explanation:

6 / 14 = 0.428571428571

0.428571428571 * 100 ~ 42.85%                

<em>Can I get Brainliest?</em>                    

6 0
4 years ago
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