Let <em>s</em> be the plane's speed in still air and <em>w</em> the wind speed. Then
<em>s</em> - <em>w</em> = (6060 km)/(6 h) = 1010 km/h
<em>s</em> + <em>w</em> = (12,150 km)/(9 h) = 1350 km/h
Adding these equations together eliminates <em>w</em> and lets you solve for <em>s</em> :
(<em>s</em> - <em>w</em>) + (<em>s</em> + <em>w</em>) = 1010 km/h + 1350 km/h
2<em>s</em> = 2360 km/h
<em>s</em> = 1180 km/h
Answer:
2000
Step-by-step explanation:
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Answer:
over the interval [2,3)
for an input value of 1.5, the corresponding output value is -2
Step-by-step explanation:
The expression is equal to 3sqrt(517)/5
243 + 62-28 = n
243 + 34 = n
277 = n
n= 277
