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AnnZ [28]
3 years ago
15

Add, subtract, multiply, or divide. Round answers to money problems to the nearest cent. Show how you solved these four problems

below:
1) $7.94 2)$ 5.37
- 4.56 + 1.92
———— ————

3) $ 1.25 4) 0.8 divided by
x 0.04 9.6
————
Mathematics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

The formatting on this is a little weird but if I'm reading it correctly:

1) 3.38

2) 7.29

3) 0.05

4) 0.42

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andreyandreev [35.5K]

Answer:

n=4

Step-by-step explanation:

We start off with 3.2n + 13.3 = 26.1.

We need to get n by itself.

Subtract 13.3 from both sides.

3.2n+13.3-13.3=26.1-13.3

26.1-13.3=12.8

We end up with: 3.2n=12.8

Divide 3.2 on both sides to get n by itself.

\frac{3.2n}{3.2} =\frac{12.8}{3.2}\\ n=4

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3 years ago
Carlos dropped the phone he had received for his birthday and broke the screen. He knows he has to pay for the replacement himse
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Answer:

you would want B

Step-by-step explanation:

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3 years ago
Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −
crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

  • \Delta = 150^2 - 4(-3)(-1200) = 8100
  • x_1 = \frac{-150 + \sqrt{8100}}{-6}
  • x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

  • \Delta = 150^2 - 4(-3)(-1800) = 900
  • x_1 = \frac{-150 + \sqrt{900}}{-6}
  • x_2 = \frac{-150 - \sqrt{900}}{-6} = 30

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

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Answer:

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