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kaheart [24]
3 years ago
8

In angle PQR, PR is extended through point R to point S, mPQR = (3x + 12),

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

m∠QRS =(10x−12)∘(10x−12) = (10(4.7) - 12) (10(4.7) - 12) = (35) (35) = 1225

Step-by-step explanation:

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This one above lol ,......................m

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4 years ago
-1/2(-3y+10) i need help combining like terms to create a equivelent expression
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Answer:

1.5y - 5

Step-by-step explanation:

I used the distributive approach and distributed -1/2 to the -3y and 10.

(If you try this and it's incorrect, you may just need to distribute -1/2 to the 10, creating -3y - 5.)

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A set of data are put in numerical order, and a statistic is calculated that divides the data set into two equal parts. Which of
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3 years ago
According to the Bureau of Labor Statistics it takes an average of 16 weeks for young workers to find a new job. Assume that the
Leya [2.2K]

Answer:

1.25% probability that 20 young workers average less than 15 weeks to find a job

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 16, \sigma = 2, n = 20, s = \frac{2}{\sqrt{20}} = 0.4472

What is the probability that 20 young workers average less than 15 weeks to find a job?

This is the pvalue of Z when X = 15. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{15 - 16}{0.4472}

Z = -2.24

Z = -2.24 has a pvalue of 0.0125.

1.25% probability that 20 young workers average less than 15 weeks to find a job

5 0
3 years ago
A sample of 31 observations is selected from a normal population. The sample mean is 69, and the population standard deviation i
Nookie1986 [14]

Answer:

the answer is 73

Step-by-step explanation:

H0: μ = 72

H1: μ ≠ 72

6 0
3 years ago
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