Question

Your Algebra 2 class has 20 students. 4 students are to be chosen at random for a project.

Answer 1

Answer:

A. 5 groups

Step-by-step explanation:

You would use multiplication for this. just think what does 4 × _ = 20? well 5! since four times give is twenty.

Answer 2

Answer:

4845

.020639% (or 1/4845)

Step-by-step explanation:

For the first one we have to use combinations (because the order doesn't matter)

The formula is as follows:

for ACB

$\frac{A!}{(A-B)!*B!}\\\\\frac{20!}{(20-4)!*4!}=4845$

2.

for probabilty the odds of an outcome is just: number of times the requirement is satisfied/total number of possibliites

we know that there are 4845 possbile groups and only one in which we get all of our friends so it's just

1/4845= .020639%