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3 years ago

What is 0.5333333333 as a fraction

2 answers:

6 0

$x=0.5\overline{3}\\
10x=5.\overline{3}\\
100x=53.\overline{3}\\
100x-10x=53.\overline{3}-5.\overline{3}\\
90x=48\\
x=\dfrac{48}{90}=\dfrac{8}{15}$

bija089 [108]3 years ago

3 0

Well Calculate the sum of 1/2 + 3*sum(n=2 to infinity) [ 1/10^n ] = 8/15 The answer would be 8/15.I hope this answer is right!

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I need help with 2 more questions ??

Tanya [424]

Answer:

x = 145 degree

Step-by-step explanation:

Alternate angle 35deg is shown alone with x on the 180 degree line opposite the other 180 degree line.

180-35 = 145degree

3 0

3 years ago

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Let X be the damage incurred (in $) in a certain type of accident during a given year. Possible X values are 0, 1000, 5000, and

KIM [24]

Answer:

$600

Step-by-step explanation:

Let the random variable $X$ denote the damage in $ incurred in a certain type of accident during a given year. The probability distribution of $X$ is given by

$X : \begin{pmatrix}0 & 1000 & 5000 & 10\; 000\\0.81 & 0.09 & 0.08 & 0.02\end{pmatrix}$

A company offers a $500 deductible policy and it wishes its expected profit to be $100. The premium function is given by

$F(x) = \left \{ {{X+100, \quad \quad \quad \quad \quad \text{for} \; X = 0 } \atop {X-500+100} , \quad \text{for} \; X = 500,4500,9500} \right.$

For $X = 0$ , we have

$F(X) = 0+100 = 100$

For $X = 500$ ,

$F(X) = 500-500+100 = 100$

For $X = 4500$ ,

$F(X) = 4500-500+100 = 4100$

For $X = 9500$ ,

$F(X) = 9500-500+100 = 9100$

Therefore, the probability distribution of $F$ is given by

$F : \begin{pmatrix} 100 & 100 & 41000 & 91000\\0.81 & 0.09 & 0.08 & 0.02\end{pmatrix}$

To determine the premium amount that the company should charge, we need to calculate the expected value of $F.$

$E(F(X)) = \sum \limits_{i=1}^{4} f(x_i) \cdot p_i = 100 \cdot 0.81 + 100 \cdot 0.09 + 4100 \cdot 0.08 + 9100 \cdot 0.02$

Therefore,

$E(F) = 81+9+328+182 = 600$

which means the $600 is the amount the should be charged.

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3 years ago

What is 7*-8? my calculator wont work because I cant do problems with negative # on it.

Jet001 [13]

7 x -8 = -56
Hope this helps! :-)

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3 years ago

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The zeros of a parabola are –4 and 2, and (6, 10) is a point on the graph. Which equation can be solved to determine the value o

Fittoniya [83]

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
y=a(x- h)^2+ k\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\stackrel{\textit{zeros\qquad \qquad \qquad }}{
\begin{cases}
x=-4\implies &x+4=0\\
x=2\implies &x-2=0
\end{cases}}
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\stackrel{\textit{factored vertex form}}{y=a(x+4)(x-2)}\qquad (6,10)\textit{ we also know that }
\begin{cases}
x=6\\
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2 years ago

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Yx divide 2 use x=7 and y=2

miskamm [114]

Answer:

finish the sentence

Step-by-step explanation:

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3 years ago