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love history [14]
3 years ago
9

(1 point) All that is left in a packet of candy are 7 reds, 3 greens, and 3 blues.

Mathematics
1 answer:
Sauron [17]3 years ago
4 0

Answer:

A 21 /169

B independent

Step-by-step explanation:

The total number of candies is 7+3+3 = 13

P( 1st red) = red/total = 7/13

Since the candy is put back there are still 13 candies in the dish

P(2nd green) = green/total = 3/13

P( red, then green) = P( 1st red) * P(2nd green)

                                = 7/13* 3/13 = 21/169

The events are independent since the candies are put back

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\huge\text{Hey there!}

\large\text{Here is your GUIDE for you to go by}\downarrow

\bullet\bold{\  \geq \ or \leq  \ will\ have\ a\ \underline{CLOSED}\ or\ \underline{SHADED\ circle}}\\\bullet\bold{\ >\ or\ \ or

\bold{\ Random\ GUIDE\ \#2}\downarrow

\bold{1. \geq is\ GREATER\ or\ EQUAL\ TO}\\\bold{2. \leq\ is\ LESS\ or\ EQUAL\ TO}\\\bold{3. >\ is\ GREATER\ THAN}\\\bold{4. < \ is\ LESS\ THAN}

“\bold{6>x}”

\bold{Well, based\ on\ your\ GUIDE\ we\ can do\ PROCESS\ OF\ ELIMINATION.}\\\\\bold{REMEMBER: < or > will\ have\ a\ O P E N E D\ circle.\ This\ throws\ A\ \& C}\\\bold{as\ your\ results\ because\ they\ are\ CLOSED\ CIRCLES\ and\ we\ are}\\\bold{looking\ for\ O P E N E D\ circles. This\ leads\ B\ & D\ as\ your\ POSSIBLE}\\\bold{result}

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\bold{Graph\ D.\ would\ be\ TOO\ BIG}

\boxed{\boxed{\bold{Answer: Option\ B.\ }}}\huge\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite40:)}

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