Answer:
y=15
DE=11
GF=17
Step-by-step explanation:
y*2=5*6
2y=30
y=15
5+6=11
15+2=17
Answer:
p
Step-by-step explanation:
lol question unclear
Answer:
254.5m^2
Step-by-step explanation:
Use the formula for the area of a circle given the radius:
A = πr^2
A = 3.14(9)^2
A = 254.47m^2
Round to the nearest tenth:
A = 254.5m^2
Problem 33
Use the distributive property on the side containing parentheses of each expression and compare it to the other side.
a) 3(5a + 3) = 15a + 9 not equal to 15a + 6
b) 2(7b - 2) = 14b - 4 not equal to 14b + 4
c) 5(2c + 3) = 10c + 15 not equal to 7c + 8
d) 3(d + 5/3) = 3d + 5 which is equal to 3d + 5
Answer for problem 33: d)
Problem 34
Use a proportion. Let the unknown number of bowls be x. The proportion is made up of two ratios that are set equal to each other. Set each ratio as a ratio of the number of avocados per bowls of guacamole. 3 avocados per 1 bowl (3/1) equals 17 avocados per x bowls (17/x).
Answer: 17/3 full bowls which is the same as 5 2/3 full bowls.
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
