Number of pieces times weight of each piece=weight of bag
25*20=500grams per 1 bag
200kg=200000g
weight of 1 bag times x bags=weight of all
500x=200000
divide both sides by 500
x=400
400 bags per day
2.
factor out 6
(6)(y^2+2y-5)=0
reemmber how if we had xy=0, assume x and/or y has to be 0?
assume that
y^2+2y-5=0
use quadratic formula
for ax^2+bx+c=0
x=
so the sum is
+
=
=
easy peasy now
1y^2+2y-5=0
-b/a
-2/1
-2 is the sum
25*20=500grams per 1 bag
200kg=200000g
weight of 1 bag times x bags=weight of all
500x=200000
divide both sides by 500
x=400
400 bags per day
2.
factor out 6
(6)(y^2+2y-5)=0
reemmber how if we had xy=0, assume x and/or y has to be 0?
assume that
y^2+2y-5=0
use quadratic formula
for ax^2+bx+c=0
x=
so the sum is
easy peasy now
1y^2+2y-5=0
-b/a
-2/1
-2 is the sum