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Andrews [41]
3 years ago
14

Please Answer!!!!

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

First mug holds the most

<em><u>Solution:</u></em>

Given that,

You are choosing between two mugs

<em><u>The volume of cylinder is given as:</u></em>

V = \pi r^2h

Where,

r is the radius and h is the height

<em><u>One has a base that is 5.5 inches in diameter and a height of 3 inches</u></em>

radius = \frac{diameter}{2}

Therefore,

r = \frac{5.5}{2}\\\\r = 2.75

Also, h = 3 inches

<em><u>Thus volume of cylinder is given as:</u></em>

V = \pi \times 2.75^2 \times 3\\\\V = 3.14 \times 22.6875\\\\V = 71.23875 \approx 71.24

Thus first mug holds 71.24 cubic inches

<em><u>The other has a base of 4.5 inches in diameter and a height of 4 inches</u></em>

Radius = \frac{4.5}{2}\\\\r = 2.25

h = 4 inches

Therefore,

V = 3.14 \times 2.25^2 \times 4\\\\V = 3.14 \times 20.25\\\\V = 63.585

Thus the second mug holds 63.585 cubic inches

On comparing, volume of both mugs,

Volume of first mug > volume of second mug

First mug holds the most

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