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Archy [21]
3 years ago
10

How does newtons first law of motion apply to a ball rolling across the gym floor after and unbalanced force is applied?

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0

Answer:

The ball will continue to roll until an unbalanced force is applied

enyata [817]3 years ago
5 0

Answer:

B

Step-by-step explanation:

B, because Newton's first law of Inertia says that an object in motion will stay in motion until an outside force acts on it.

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2 1/2 1 1/16 = 3 1/16 3 1/2 3 9/16 3 3/16
amm1812
2 1/2     = 2 8/16

so

2 8/16  + 1 1/16    = 3 9/16

The answer is the third option



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3 years ago
$29000; 4 percent decrease
yulyashka [42]
The easiest way to calculate this, since you don't need to know what the discount is, if the decrease is 4% you still have 96%. Multiply 29,000 x .96= $27,840. If you do it the other way, .04 x 29000= 1160. Then subtract 29000-1160=27850.
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3 years ago
Find the lateral area of the square pyramid shown, to the nearest whole number.
mylen [45]
I believe the correct answer is D)
3 0
3 years ago
Read 2 more answers
A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
kati45 [8]

Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

6 0
3 years ago
Read 2 more answers
The larger of two numbers is 15 more than three times the smaller number. If the sum of the two numbers is 63, find the numbers.
tangare [24]
The larger number is 51 and the smaller number is 12. ( hope I helped) have a good day
3 0
3 years ago
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