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Archy [21]
3 years ago
10

How does newtons first law of motion apply to a ball rolling across the gym floor after and unbalanced force is applied?

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0

Answer:

The ball will continue to roll until an unbalanced force is applied

enyata [817]3 years ago
5 0

Answer:

B

Step-by-step explanation:

B, because Newton's first law of Inertia says that an object in motion will stay in motion until an outside force acts on it.

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Plz help ................................
Elodia [21]

Answer:

1/4 is correct, or .25 in decimal form

Step-by-step explanation:

7 0
3 years ago
Last week, Riley worked 7.5 hours per day for 3 days and earned a total of $306.45.
maria [59]

Answer:

13,62$

Step-by-step explanation:

The total hours Riley worked last week: 7.5*3= 22.5 (hours)

Riley's hourly rate of pay: 306.45/ 22.5= 13.62$

8 0
3 years ago
Read 2 more answers
Graph the equation on the coordinate plane.y=2x-1
Yakvenalex [24]

This equation is written in slope intercept form

Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

In this case:

slope (m) is 2

y-intercept (b) is (0, - 1)

To plot this on a coordinate plane plot the y-intercept (0, -1).

To graph the rest of the line you can use what you know about the slope. Rise up two units and over to the right one unit from the y-intercept. You should arrive at the point (1, 1)

Then, again from the y-intercept, go down two units and to the left one unit. You should arrive at the point (-1, -3)

Now draw a straight line through the y-intercept and the other two points you just found

The image of the graph is shown below

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
PLEASE HELP!!! ASAP!!!!!!!!!!!!!!! 10 POINTS
I am Lyosha [343]
1800|2\\.\ 900|2\\.\ 450|2\\.\ 225|5\\.\ \ 45|5\\.\ \ \ 9|3\\.\ \ \ 3|3\\.\ \ \ 1|\\\\1880=2\cdot2\cdot2\cdot5\cdot5\cdot3\cdot3=2^3\cdot5^2\cdot3^2\\\\Answer:\ \boxed{2^3\cdot3^2\cdot5^2}

\sqrt[3]{320}\\\\320|2\\160|2\\.\ 80|2\\.\ 40|2\\.\ 20|2\\.\ 10|2\\.\ \ 5|5\\.\ \ 1|\\\\320=2\cdot2\cdot2\cdot2\cdot2\cdo2\cdot5=2^3\cdot2^3\cdot5=2^3\cdot2^3\cdot\\\\\sqrt[3]{320}=\sqrt[3]{2^3\cdot2^3\cdot5}=\sqrt[3]{2^3}\cdot\sqrt[3]{2^3}\cdot\sqrt[3]{5}=2\cdot2\sqrt[3]{5}=4\sqrt[3]5\\\\Answer:\ \boxed{\sqrt[3]{320}=4\sqrt[3]{5}}
4 0
3 years ago
Read 2 more answers
What is the equation of the circle center (0, 3) and radius 4?
Sunny_sXe [5.5K]

Answer:

( x )² + ( y - 3 )² = 16

Step-by-step explanation:

The general format for circular equations is ( x - a )² + ( y - b )² = r²

3 0
3 years ago
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