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3 years ago

PLSSSSSSS HELP ME I DON'T KNOW WHAT TO DO

Mathematics

2 answers:

AURORKA [14]3 years ago

4 0

Step-by-step explanation:

x is the number of bulbs.

We have $2x + $4 = $20.

=> $2x = $16, x = 8.

Hence Sheila can order 8 flower bulbs.

OverLord2011 [107]3 years ago

3 0

Answer:

8 bulbs

Step-by-step explanation:

In the model, each + represents a dollar

4 +s for the shipping cost, 20 +s for the total cost.

Therefore we have 2x (since each bulb is $2) + 4 = 20

2x = 16

x = 8

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Find the greatest common factor of the following monomials 34n^5 32n4

Andrew [12]

Answer:

by u meant 32n^4, then the answer is 2n^4

Step-by-step explanation:

first find the gcf of the coefficient

32 and 34

their gcf is 2, because they're both even but have no other common factor, so it is 2

then for the variables

n^4 and n^5

their gcf is n^4. you can tell by dividing each term by n^4

n^4 / n^ 4 = 1

n^5 / n^4 = n

so then 2 * n^4 is 2n^4

7 0

3 years ago

Read 2 more answers

The ratio of the circumference of two circles is 3:2.What is the ratio of their area

Nezavi [6.7K]

The ratio of their area is 9/4

<h2>Explanation:</h2>

We use ratios to compares values. In this exercise, we are comparing the circumference of two circles, which is:

$3:2$

and we want to know what is the ratio of their area. Recall that the circumference of a circle is given by:

$C=2\pi r \\ \\ \\ Where: \\ \\ C:Circumference \\ \\ r:Radius \ of \ the \ circle$

If we define:

$C_{1}: \ Circumference \ of \ circle \ 1 \\ \\ C_{2}: \ Circumference \ of \ circle \ 2 \\ \\ r_{1}: \ Radius \ of \ circle \ 1 \\ \\ r_{2}: \ Radius \ of \ circle \ 2$

Then, the ratio of the circumference of two circles is 3:2 is:

$\frac{C_{1}}{C_{2}}=\frac{2\pi r_{1}}{2\pi r_{2}}=\frac{3}{2} \\ \\ \therefore \frac{r_{1}}{r_{2}}=\frac{3}{2}$

The area of a circle is given by:

$A=\pi r^2 \\ \\ A:Area \\ \\ r:Radius$

So the ratio of their area can be found as:

$\frac{A_{1}}{A_{2}}=\frac{\pi r_{1}^2}{\pi r_{2}^2} \\ \\ \\ A_{1}:Area \ of \ circle \ 1 \\ \\ A_{2}:Area \ of \ circle \ 2$

So:

$\frac{A_{1}}{A_{2}}=\frac{r_{1}^2}{r_{2}^2}=\left( \frac{r_{1}}{r_{2}} \right)^2 \\ \\ \frac{A_{1}}{A_{2}}=\left(\frac{3}{2}\right)^2 \\ \\ \boxed{\frac{A_{1}}{A_{2}}=\frac{9}{4}}$