Question

Juanita is making necklaces to give as presents. She plans to put 15 beads on each necklace. Beads are sold in packages of 20. What is the least common number of packages she can buy to make necklaces and have no beads left over?

Answer 1

Answer: 3

Step-by-step explanation:

Given : Juanita is making necklaces to give as presents.

She plans to put 15 beads on each necklace. Beads are sold in packages of 20.

To find the least common number of packages she can buy to make necklaces and have no beads left over,  First we need to find the least common multiple of 15 and 20.

Since , $15=3\times5\\\\20=2\times2\times5$

Then least common multiple of 15 and 20 =$2\times2\times3\times5=60$

Now, the least common number of packages she can buy to make necklaces and have no beads left over =$\dfrac{60}{20}=3$.

Hence, the least common number of packages she can buy to make necklaces and have no beads left over=3

Answer 2

Hi there!

It should be 4 packages, with some mental math.

4 * 20 = 80

4 * 15 = 60

Remember we still have 20 beads left over now. Add it to 60 and bam! You're done!