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exis [7]
3 years ago
15

I GIVEEEE BRAINLILSTT

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
Alr bet x + 8 y - 9 :)
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3x + 9x simplified pls
Rudik [331]

Answer:

12x     i hope this helps!    :_

Step-by-step explanation:

3x + 9x = 12x

3 + 9 = 12

7 0
3 years ago
The graph of the function f(x) = -(x+6)(x + 2) is shown
Leokris [45]

Answer:

The function is increasing for all real values of x where

x < –4.

Step-by-step explanation:

we have

f(x)=-(x+6)(x+2)

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex (h,k) represent  a maximum

The roots of the function (or x-intercepts) are x=-6 and x=-2

The x-coordinate of the vertex is the midpoint of the roots

so

h=(-2-6)/2=-4

The y-coordinate of the vertex is

substitute the x-coordinate of the vertex in the quadratic equation

k=-(-4+6)(-4+2)

k=-(2)(-2)

k=4

The vertex is the point (-4,4)

The function is increasing in the interval (-∞,-4)

The function is decreasing in the interval (-4,∞)

6 0
3 years ago
Read 2 more answers
Find the missing side lengths. Leave your answer as radicals in simplest form.
nika2105 [10]

\sqrt{2Answer:

Step-by-step explanation:

take 45 degree as reference angle

use sin rule

sin 45=opposite/hypotenuse

1/\sqrt{2=x/2\sqrt{2

do cross multiplication

x\sqrt{2=\sqrt{2 *\sqrt{2

x\sqrt{2=2

x=2/\sqrt{2

x=\sqrt{2

pythagoras theorem

a^2+b^2=c^2

(\sqrt{2 )^2+y^2=(2\sqrt{2 )^2

2+y^2=8

y^2=8-2

y=\sqrt{6

7 0
3 years ago
PLEASE
Svet_ta [14]

Answer:

I don't know the answer to your question sorry but can u give me brainliest

7 0
3 years ago
Simplify w/ positive values
Licemer1 [7]
\bf \sqrt{\cfrac{3x^5}{75x^9}}\qquad &#10;\begin{cases}&#10;75=3\cdot 5\cdot 5\to 3\cdot 5^2\\&#10;x^9\to x^{5+4}\to x^5\cdot x^4&#10;\end{cases}\qquad thus&#10;\\\\\\\\&#10;\sqrt{\cfrac{3x^5}{3\cdot 5^2\cdot x^5\cdot x^4}}\implies \sqrt{\cfrac{3x^5}{3x^5}\cdot \cfrac{1}{5^2x^4}}\implies \sqrt{1\cdot \cfrac{1}{5^2x^4}}&#10;\\\\\\\\&#10;\sqrt{\cfrac{1}{5^2x^4}}\qquad &#10;\begin{cases}&#10;1^2\to 1\\&#10;x^4\to x^{2\cdot 2}\to (x^2)^2&#10;\end{cases}\qquad thus&#10;\\\\&#10;

\bf \sqrt{\cfrac{1}{5^2x^4}}\implies \sqrt{\cfrac{1^2}{5^2(x^2)^2}}\implies \sqrt{\cfrac{1^2}{(5x^2)^2}}\implies \sqrt{\left( \cfrac{1}{5x^2} \right)^2}&#10;\\\\\\&#10;\cfrac{1}{5x^2}
6 0
4 years ago
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