Help please!!

2. A function g(x) is defined by the diagram shown below.

skad [1K]

Answer:

Step-by-step explanation:

diagram attached represents a function g(x).

Circle (1) (circle on the left) represents the set of domain (input values) and circle (2) represents the range (output values).

a). For input value x = 7, out put value of the function is y = 9.

Therefore, g(7) = 9 will be the answer.

b). Range of the function g(x) is the set of output values.

Range: {12, 9, 9, 17}

c). Inverse of the function g(x) will have,

Domain: {12, 9, 9, 17}

Range: {4, 7, 10, 15}

For input value of x = 9, there are two output values y = 7, 10.

Since, "a function can't have two output values for the same input value".

Therefore, inverse of the function g(x) will not represent a function.

8 0

4 years ago

A child is standing across the street from his apartment. His mother is on their balcony. The angle of elevation between the chi

Alenkinab [10]

Hwuaijshwjshjwjwjwhjwjwbbwbjw

4 0

3 years ago

In Store A, a book that regularly sells for $24.99 is on sale at 15% off. In Store B the same book regularly sells for $27.99 an

stealth61 [152]

Answer: Store B

Step by Step
divide the the normal price of the book by four to get the amount of the book on sale in store B which is $21. To get the answer for Store A divide the normal price of the book by ten then divide the amount you get by 2 and add the two amounts up to get the the amount of the book on sale which is $21.26

8 0

3 years ago

Factor:

nekit [7.7K]

Answer:

a) $(7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)$

b) $(7\cdot a\cdot b^{8}+1)\cdot (7\cdot a\cdot b^{8}-1)$

c) $a = 0.7\cdot t^{9}$

d) There are two possible answers only considering real coefficients:

(i) $16\cdot x^{2}-81 = (4\cdot x +9)\cdot (4\cdot x - 9)$

(ii) $14\cdot x^{2}-81 =(\sqrt{14}\cdot x+9)\cdot (\sqrt{14}\cdot x - 9)$

e) $(a^{3}+4)\cdot (a^{3}-4)$

Step-by-step explanation:

Now we proceed to solve each algebraic equation:

a) Factor $49\cdot m^{12}-16$

This binomial is of the form $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . In this case, we can rewrite and factor the equation below:

$49\cdot m ^{12}-16$

$(7\cdot m^{6})^ 2-4^{2}$

$(7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)$

b) Factor $49\cdot a^{2}\cdot b^{16}-1$

This binomial is of the form $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . In this case, we can rewrite and factor the equation below:

$49\cdot a^{2}\cdot b^{16}-1$

$(7\cdot a\cdot b^{8})^{2}-1^{2}$

$(7\cdot a\cdot b^{8}+1)\cdot (7\cdot a\cdot b^{8}-1)$

c) Nicole is factoring $0.49\cdot t^{18}-25$ by using the rule $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . What will she use for the value of $a$ ?

From this rule we find that $a^{2} = 0.49\cdot t^{18}$ , that is:

$a^{2} = 0.49\cdot t^{18}$

$a^{2} = \frac{49}{100}\cdot t^{18}$

$a = \frac{7}{10}\cdot t^{9}$

$a = 0.7\cdot t^{9}$

d) Which binomial is a difference of squares?

A binomial is a difference of square if and only if $a^{2}-b^{2} = (a+b)\cdot (a-b)$ . There are two possible answers only considering real coefficients:

(i) $16\cdot x^{2}-81 = (4\cdot x +9)\cdot (4\cdot x - 9)$

(ii) $14\cdot x^{2}-81 =(\sqrt{14}\cdot x+9)\cdot (\sqrt{14}\cdot x - 9)$

e) Factor $a^{6}-16$