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3 years ago

What’s 51/3- 41/2= pleas help

Mathematics

1 answer:

hjlf3 years ago

3 0

The answer is -7/2. In decimal it is -3.5.

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Evaluate: 24 divided (8 -2)

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Answer:

Step-by-step explanation:

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(10 points) Given that for simplicity that the number of children in a family is 1, 2, 3, or 4, with probability 1/4 each. Littl

sesenic [268]

1/4 ... it’s 2 because 1/4 is it yep ya it’s right

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3 years ago

5.3.21<br>Solve the equation P= r+t+s for r<br>(Simplify your answer.)

Sever21 [200]

Answer:

r = P -t -s

Step-by-step explanation:

This is a one-step linear equation in r. Subtract the terms that don't contain r:

P = r + t + s . . . . . . . . . . given

The terms on the right that don't include r are (t+s). We want to subtract that to get r by itself.

P -(t+s) = r +(t+s) -(t+s) . . . subtract (t+s)

P -t -s = r . . . . . . . . . . . . . . simplify

r = P - t - s

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4 years ago

An Arctic turn can fly more than 43,496 miles as it migrate each year round this number to the nearest ten thousand miles then r

ollegr [7]

The answer is 40,000 thousands 43 is closer o 40

4 0

3 years ago

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On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers