4 years ago

Ms. Johnson asked her class to write an equivalent

1 answer:

8 0

Ahmad wrote the correct expression.
To prove that 7(2d + 3k - dk) - 7 is equal to 14d - 9 + 21k - 7dk + 2
Please check this solution:
7(2d + 3k - dk) - 7 = 14d - 9 + 21k - 7dk + 2
7(2d + 3k - dk) - 7 = 14d + 21k - 7dk -9 + 2
7(2d + 3k - dk) - 7 = 14d + 21k - 7dk -7

Get the common variable which is 7.
7(2d + 3k - dk) - 7 = 7(2d + 3k - dk) - 7

For checking, we can simplify the equation...
from 7(2d + 3k - dk) - 7 = 14d - 9 + 21k - 7dk + 2
We simplify it to:
7(2d + 3k - dk) - 7 = 14d + 21k - 7dk -7
7 * 2d = 14d
7 * 3k = 21k
7 * - dk = -dk

Therefore,
7(2d + 3k - dk) - 7 is equal to 14d + 21k - 7dk -7

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line m passes through point (-2,-1) and is perpendicular to the graph of y=-2/3x+6. Line n is parallel to line m and passes thro

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Answer:

Hello...... here is a solution :

1 -

Hello:

the equation of "m" is : y = ax+b

the slope is a : a×(- 2/3) = -1......( perpendicular to a line : y=-2/3x+6 when the slope is -2/3 )

a = 3/2

the line " n" that passes through (4, - 3) and parallel to line "m" :

when the slope is 3/2 ( same slope )