V^2/(1-v^2/c^2)=R
v^2=R(1-v^2/c^2)
v^2=R-Rv^2/c^2
v^2-Rv^2/c^2=R
v^2(1-R/c^2)=R
v=sqrt(R/(1-R/c^2))
where R was original right side, dont forget plus minus
Answer:
Step-by-step explanation:
Given is a function of x
When y=0 we get x=0 and infinity
Hence x intercept is 0 and one asymptote is x axis.
When x=0 , y =0
Maxima at x=1, and point of inflection is at x=2
Increasing upto x=1 and then decreases
Graph is enclosed
Draw a right triangle to represent the problem.
The vertical height of the triangle is 9 ft, and it represents the tree.
The horizontal length, at the bottom of the tree is ground level and has a length of 13 ft.
Let x = angle of elevation.
By definition,
tan x = 9/13 = 0.6923
x = arctan(0.6923) = 34.7 deg. = 35 deg (approx)
Answer: 35°
1. AB 3-2/-1-1
-1/2
BC 2+1/1+3
3/4
AC 3+1/-1+3
4/2=2
It is a right triangle
2. JK -1-2/4+3
-3/7
LM -2+5/-5-2
-3/7
KL -1+5/4-2
<u>4/2=2</u>
JM 2+2/-3+5
<u>4/2=2
</u><u />The quadrilateral is a parallelogram
Answer:
8.1
Step-by-step explanation:
2x^2 -9 = 121
+9 +9
2x^2 = 130
/2 /2
x^2 = 65
x= sqrt (65)
x= 8.06225...
x = 8.1
