Answer:
d) 5/12
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Drinks:
Five diet, 10 regular.
Probability of a regular drink:
10/(10+5) = 10/15 = 2/3
Regular bag of chips:
6 fat-free, 10 regular
Probability of a regular bag of chips:
10/(10+6) = 10/16 = 5/8
What is the probability that you will buy a regular drink and a regular bag of chips?
Drink and chips are independent events, which means that we just multiply the probabilities. So

The correct answer is given by option d.
Simplest form of 12/15 is 4/5
To simplify the fraction, you need to divide both numerator (12) and denominator (15) by a number that goes into both numbers which is 3. You then end up with your fraction
Answer:
the answer should be x= -9 over 11
Step-by-step explanation:
Answer:

Step-by-step explanation:
Since the divisor of
is in the form of
use what is called Synthetic Division. Remember, in this formula, −c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
−1| 2 1 0 1
↓ −2 1 −1
__________
2 −1 1 0 → 
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [2x³ + x² + 1]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than the leading coefficient of your dividend, so that 2 in your quotient can be a 2x², the −x follows right behind it, and bringing up the rear, 1, giving you the quotient of 2x² - x + 1.
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<u>Options</u>
Answer:
(B)
Step-by-step explanation:
We know that the External Angle = Half the Difference of the Two Arcs
Therefore:
Since FGH is the exterior angle and FEH and FH are the two arcs, then:

Also:

Adding the two equations, we have:
