If 9/10 tons of gravel got spread over 3 feet, then how much gravel is on each foot? Well, it's a ratio.
9/10 tons : 3 ft
So, we divide each side of the ratio by 3.
3/10 tons : 1 ft.
So, that 3/10 tons of gravel on each foot of road.
We have (x-4)/(-6-4) = (y-4)/(-4-4);
(x-4)/(-10) = (y-4)/(-8);
(x-4)/5 = (y-4)/4;
4x-16 = 5y-20;
4x - 5y + 4 = 0;
The negative exponents that are in the numerator pass to positive if the base is moved to the denominator, and the negative exponents that are in the denominator pass to positive if the base is moved to the numerator.
The the answer is the option B: xx^4 / y^2 y^6
Answer:
can you add a paper or more info to answer
Step-by-step explanation:
