The length of a rectangle is (3x-2) and its width is (2x+1). Find algebraic expressions to represent both the perimeter and area
of this rectangle
1 answer:
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Step-by-step explanation:
Actual graph for this problem is attached below
m∠TUV = 167°
m∠TUL = (x + 11)°
m∠LUV = (11x)°
m∠TUV= m∠TUL+ m∠LUV
now plug in the angles for each
m∠TUV= m∠TUL+ m∠LUV
solve the equation for x
Subtract 11 from both sides
divide both sides by 12
x=13
m∠TUL = (x + 11)°
m∠TUL = (13+ 11)° = (24)°
answer:
24°
