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3 years ago

15

The length of a rectangle is (3x-2) and its width is (2x+1). Find algebraic expressions to represent both the perimeter and area

of this rectangle

1 answer:

Alenkasestr [34]3 years ago

4 0

Answer:

Perimeter = 10x-2

Area = 6x²-x-2

Step-by-step explanation:

Perimeter=2L+2W

2(3x-2)+2(2x+1)

6x-4+4x+2

10x-2

Area=LW

(3x-2)(2x+1)

6x²+3x-4x-2

6x²-x-2

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3 years ago

Any line with no slope is parallel to the<br><br> *x-axis<br> *y-axis<br> *line y = x

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The x-axis.

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3 years ago

Your Numbers are; 25, 75, 50, 1, 9, 3 and your Target is 386 How do i get to 386 using only these numbers once and I can use Sub

GuDViN [60]

Answer:

You must order the operations in the way that it unfolds in the explanation;:

Step-by-step explanation:

(25 x 9) +75 + 50+ 9 x ( 3 + 1)

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3 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

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