A.) Bisecting Diagonals
B.) Four right angles
D.) Two pair of opposite parallel sides
E.) Two pair of opposite congruent sides
Hope this helps!
Answer:
the answer would be a
Step-by-step explanation:
Answer:
1 2/3 hope this helps and have a wonderful day
The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
<h3>Determining the perimeter and area of the triangle giving line equation</h3>
In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.
The points of intersection of the line are;
(x₁, y₁) = (- 0.4, 5.2),
(x₂, y₂) = (-0.8, 4.4),
(x₃, y₃) = (0, 4)
Determine the base
b² = c² -a²
b = √(-0.8)² + (4 - 4.4)²
b = 2√5 / 5
Determine the height
h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²
height = 2√5 / 5
For the hypotenuse
r = √2 · b
r = 2√10 / 5
<h3>Determine the Perimeter and area</h3>
Perimeter = s1+s2+s3
Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5
Perimeter = (2√10 + 4√5) / 5 units
<u>For the area</u>
area = 1/2* base * height
A = 0.5 · (2√5 / 5) · (2√5 / 5)
A = 2/5 square units
Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
Learn more on area and perimeter of triangles here: brainly.com/question/12010318
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Kevin installed a certain brand of automatic garage door opener that utilizes a transmitter control with four independent switches, each one set on or off. The receiver (wired to the door) must be set with the same pattern as the transmitter. If six neighbors with the same type of opener set their switches independently.<u>The probability of at least one pair of neighbors using the same settings is 0.65633</u>
Step-by-step explanation:
<u>Step 1</u>
In the question it is given that
Automatic garage door opener utilizes a transmitter control with four independent switches
<u>So .the number of Combinations possible with the Transmitters </u>=
2*2*2*2= 16
<u>
Step 2</u>
Probability of at least one pair of neighbors using the same settings = 1- Probability of All Neighbors using different settings.
= 1- 16*15*14*13*12*11/(16^6)
<u>
Step 3</u>
Probability of at least one pair of neighbors using the same settings=
= 1- 0.343666
<u>
Step 4</u>
<u>So the probability of at least </u>one pair of neighbors using the same settings
is 0.65633