22 +3=(2−1)(+1) Pls help

Can anyone help me with this Midterm Advanced Algebra problem. (DONT ANSWER IF YOUR NOT SURE)

steposvetlana [31]

Answer:

B

Step-by-step explanation:

If you take a lokk at the picture I used an online algebra calculator to check my answer against to gurantee the corectness of my answer for you.

7 0

3 years ago

Write an equation of the line that passes through (−5, −1) and is parallel to the line y = 4x − 6.

vaieri [72.5K]

Answer:

The equation is y = 4x + 19

Step-by-step explanation:

y = 4x - 6 Using y = mx + b, the slope = 4.

Parallel lines have the same slope.

Now substitute the slope = 4 and the given ordered pair (-5, -1) into the slope-intercept form and solve for b.

y = mx + b

-1 = 4(-5) + b

-1 = -20 + b

19 = b

Now substitute into y = mx + b m = 4 and b = 19

The equation is y = 4x + 19

8 0

3 years ago

Find the equation of the line that is perpendicular to the line y = 4 and passes through the point (-2, 1).

mojhsa [17]

Answer:

x = - 2

Step-by-step explanation:

y = 4 is the equation of a horizontal line parallel to the x- axis.

Thus a perpendicular line will be vertical and parallel to the y- axis.

The equation of a vertical line is

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (- 2, 1) with x- coordinate - 2, thus

x = - 2 ← equation of perpendicular line

5 0

4 years ago

Read 2 more answers

Ten key is making a square frame for her painting.She is using 4pieces of wood that are each 2.75 feet long.how much wood will t

Bad White [126]

Answer:

she will use 11ft of wood in total

Step-by-step explanation:

all you have to do is add 2.75 to its self four times.

7 0

3 years ago

Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC

Vinvika [58]

According to the midsegment theorem, the midsegments are parallel to

and half the length of the opposite side.

The completed statement are as follows;

Because the slopes of $\overline{EF}$ and $\overline{AC}$ are both -4, $\overline{EF}$ ║ $\overline{AC}$

EF = $\underline{\sqrt{17}}$ and AC = $\underline{2 \cdot \sqrt{17} }$

Because $\underline{\sqrt{17} }$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17} }$ , $EF = \frac{1}{2} \cdot AC$

Reasons:

From the given graph of ΔABC, we have;

Coordinates of the points A, B, and C are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on $\mathbf{\overline{DE}}$ are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)} = \frac{-8}{2}} = -4$

$\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)} = \frac{4}{-1} = -4$

$Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}$

Length of EF = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of $\mathbf{\overline {EF}}$ and $\mathbf{\overline {AC}}$ are both , -4, $\overline {EF}$ ║ $\overline {AC}$ . EF = $\underline{\sqrt{17}}$ , and AC

= $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ ,. Because $\underline{\sqrt{17}}$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ , $EF =\mathbf{ \frac{1}{2} AC}$

Learn more about midsegment theorem of a triangle here:

brainly.com/question/7423948

8 0

3 years ago