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olya-2409 [2.1K]
3 years ago
15

Rewrite the following equation in standard form and determine if there is a solution.

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

| x + 4 |  = -1    No solution

Step-by-step explanation:

                                                 3 | x + 4 | + 12 = 9

Subtract 12 from both sides:         3 | x + 4 |  = -3

Divide both sides by 3:                     | x + 4 |  = -1

Absolute value cannot be negative, so there is no solution.

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Can someone please help me?!?! I need this done before 1-5-21
Travka [436]

Answer:

8=w, -8=w  (±8=w)

Step-by-step explanation:

192=3w^{2}

First, divide by 3

64=w²

now take the square roots of 64 and w² ( we're thinking about which numbers/variables will be multiplied to get 64 and w². They are 8 and w. But wait! -8 can also work, since when you square it a negative number, it will turn positive. )

8=w, -8=w

You can also write it as ±8=w

Hope this helps!

6 0
3 years ago
Number 30, please help
GREYUIT [131]

Answer:

correct

Step-by-step explanation:

Imagine a point in the top left quadrant of a graph

when you rotate it 180 degrees it will end up in the bottom right quadrant

The same will apply if you flip on the y axis and the x axis in no given order

3 0
4 years ago
Read 2 more answers
HELP ME!!!! I need to submit it and make sure to ANSWER BOTH! 1 AND 2 last time people only answer 1 if you answer both ill give
marshall27 [118]

Answer:

The first one is 14.5 and the second one is that the decimal moves to the left every time a zero is added to the first number

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Search results for "A shipment of 18 cars, some weighing 3,000 pounds, and the others weighing 5,000 pounds each. Together the s
kkurt [141]
The best way to solve a problem like this is to set up two equations. First assign a variable to each thing you are trying to find. In this case, it's two different kinds of cars. Let's call the cars that weigh 3,000 pounds x, and the ones that weigh 5,000 y. The two equations you should write are:

 x+y=18 (because the problem tells you there were 18 cars in total)
3000x+5000y=60000 (because that is the total weight in the problem)

Next, you need to solve for one of the variables. I will solve for x first by subtracting y from both sides of the first equation.

x=18-y

Then you have to plug that into the other equation to get:

3000(18-y)+5000y=60000

Simplify and solve for y:

54000-3000y+5000y=60000
54000+2000y=60000
2000y=6000
y=3

Now that you know what y equals, you can put it into the equation we solved for x:

x=18-3
x=15

So there are 15 cars that weigh 3000 pounds and 3 that weigh 5000.
4 0
4 years ago
Read 2 more answers
If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below.
Sati [7]
Sub 2 for x in j(x) and evalueate
then sub that result for x in h(x)

j(2)=-2(2)
j(2)=-4

now sub-4 for  x in h(x)

h(-4)=5(-4)-3
h(-4)=-20-3
h(-4)=-23

answer is -23
8 0
3 years ago
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