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Lucy is a dress maker. She sews 4/7 of a dress in 3/4 hour. Lucy sews at a constant rate. At this rate, how many dresses does Lu

MAVERICK [17]

Answer:

16/21 dresses

Step-by-step explanation:

3/4 · k hours: 4/7 · k dresses for any constant k

If we want 1 hour, then k will need to be 4/3

4/3 × 4/3 hours: 4/7 × 4/3

1 hour = 16/21 dresses

7 0

3 years ago

a drawer contains 9 white paper clips, 5 green paper clips, and 6 red paper clips. One paper clip is selected at random. What is

tatyana61 [14]

Answer:

the answer should be 9/14

Step-by-step explanation:

you add them all up then subtract the red for your denominator

then just put the number of white on top for your numerator

6 0

3 years ago

Read 2 more answers

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

mauricio estimates that the first module of the project could be completed in as few as 15 days or could take as many as 25 days

4vir4ik [10]

Answer:

Most likely time, according to PERT (Program evaluation and review technique).

Step-by-step explanation:

PERT is "a statistical tool used in project management" (Program evaluation and review technique (2020), in Wikipedia), and it is commonly used with CPM (Critical Path Method) to manage projects.

Inside PERT, there are different defined times to accomplished an activity in a project, that is:

An optimistic time or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
A pessimistic time, a time quite the opposite to optimistic time.
A most likely time, or a time required to accomplished an activity if everything goes as expected or normally.
An expected time, an statistical estimation.

Considering the question, we have that the time when "the first module of the project could be completed":

"[...] in as few as 15 days" is the optimistic time.
"[...] or could take as many as 25 days" is the pessimistic time.
"[...] but most likely will require 20 days" is the most likely time.

As a result, the 20-day estimate is called the most likely time in the context of the PERT/CPM techniques.

3 0

3 years ago

Work out the value of 5^8 x 5^-2 / 5^4

IrinaK [193]

Answer:

the answer is 25

Step-by-step explanation:

7 0

3 years ago