Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
-15 degrees
Step-by-step explanation:
3 times 5 is 15 and its negative because it says it DROPS every hour and its taking the temp every 5 hrs
Answer:
The correct answer is 0.486.
Step-by-step explanation:
Total number of employees at the home office of Gibraltar Insurance Company is 270 + 340 = 610
Number of employees on flex time are 350, out of which 170 are men and 180 are women.
We need to find the probability that out of the given employees, a randomly chosen one is on flex time and is a man.
Favorable outcomes are 170 and total outcome is 350.
Thus the probability is given by 
= 0.4857≈ 0.486
