A=l*w
161=14w
161/14=w
11.5cm is the width
Answer:
B and D
7/12 cups
Step-by-step explanation:
2 1/3 + 2 1/4 = cups of flour needed
4 = cups of flour had
2 1/3 + 2 1/4
To have the same denominator, we take the lcm
2 + 2 + (4/12 + 3/12) =
2 4/12 + 2 3/12 - 4
Or
2 + 2 + (3 + 4) / 12 - 4
2 + 2 + (3 + 4) / 12 - 4 = 4 7/12 - 4
4 7/12 - 4 = 7/12 cups of flour needed
Answer:
184 in²
Step-by-step explanation:
Given :
Width, w = 6 inches
Length, l = 10 inches
Height, h = 2 inches
To obtain how much wrapping paper is needed ; we take the surface area of the box
Surface area = 2(lw + lh + wh)
Surface area = 2((6*10) + (6*2) + (10*2))
Surface area = 2(60 + 12 + 20)
Surface area = 2(92)
Surface area = 184 in²
The amount of wrapping paper needed = 184 in²
Answer:
9,951.04
Step-by-step explanation:
First you find the area of the rectangle:
44x88=3,872
Then you add the area of the two semi circles:
A=1/2(pi)(r^2)
A= 3,039.52
Multiply the area above by 2 since there are two semi circles and they are the same size.
