Question

Please help! x^3 +y^3=9

Answer 1

Step-by-step explanation:

Taking the derivative of both sides with respect to x, we get

$\dfrac{d}{dx}(x^3 + y^3) = \dfrac{d}{dx}(3)$

$\Rightarrow 3x^2 + 3y^2\dfrac{dy}{dx} = 0$

Solving for $\frac{dy}{dx}$, we get

$\dfrac{dy}{dx} = -\dfrac{3x^2}{3y^2} = -\dfrac{x^2}{y^2}$