Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
K=5
if you add 5 to f(x) it will move up five and become g(x)
Answer:
One ticket equals $169
Step-by-step explanation:
The family buys 4 airline tickets online.
The travel insurance costs $19 per ticket.
The total cost is $752.
A.
An equation that models this problem could be
Basically, we know that the insurance costs $19 which represents an additional costs after the price per ticket, that's why we need to add them. Then, we know that the familiy bought 4 tickes, that's why we multiply by 4, and finally, the total cost must be equal to 752, according to the problem.
B.
To find the price of one ticket, we just need to solve the equation for
Therefore, one ticket costs $169.
The diameter of the circle is needed. But to solve, you would simply multiply the diameter of the circle by pi (3.14).
Answer:
A histogram is a bar graph that represents grouped data
