1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aliun [14]
3 years ago
15

Solve for p. 2(p + 1) = 18

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Answer:

p = 8

Step-by-step explanation:

Subtract 18 from behind the equal sign to cancel it out. This leaves you with 2(p+1)- 18= 0.

Next you'll need to pull out the terms to work with the beginning of the problem. 2(p+1)- 18= 0 would turn into 2p - 16  = 2(p - 8).

This would leave you with 2= 0, but that's not true so continue on to the variable.

So p - 8= 0 making the answer p = 8

You might be interested in
HELP PLEASE !!! Place each expression under the equivalent expression in the table.
tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

1). \frac{(x-4)(x+2)}{x^{2}+5x+6}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{x^{2}+3x}{(x+3)(4x-5)}

=\frac{x(x+3)}{(x+3)(4x-5)}=\frac{x}{4x-5}

2). \frac{3x}{4x-5}-\frac{4x^{2}}{8x^{2}-10x}=\frac{3x}{4x-5}-\frac{4x}{8x-10}=\frac{3x(8x-10)-4x(4x-5)}{(4x-5)(8x-10)}

=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}

=\frac{8x^{2}-10x}{(4x-5)(8x-10)}=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}

3). \frac{6x^{2}}{x^{2}-7x+10}\div \frac{2x}{x-5}

=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}

=\frac{3x(x-5)}{x^{2}-7x+10}

=\frac{3x(x-5)}{(x-5)(x-2)}=\frac{3x}{x-2}

4). \frac{-x}{4x-5}-\frac{4x^{2}}{16x^{2}-22x}

=\frac{-x}{4x-5}-\frac{2x}{8x-11}

=\frac{-x(8x-11)-2x(4x-5)}{(4x-5)(8x-11)}

=\frac{-8x^{2}+11x-8x^{2}+10x}{(4x-5)(8x-11)}

=\frac{-16x^{2}+21x}{(4x-5)(8x-11)}=\frac{-x(16x-21)}{(4x-5)(8x-11)}

5). \frac{3x^{2}}{x+3}\times \frac{2(x+3)}{2x^{2}-4x}

=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}

6). \frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}

=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}

4 0
3 years ago
Read 2 more answers
Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year)
jenyasd209 [6]

Answer:

110\ \text{km/myr} =11\ \text{cm/yr}

Step-by-step explanation:

To find : Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year) ?

Solution :

Using metric conversions,

1 kilometer = 1000 meter

1 meter = 100 centimeter

So, 1 kilometer = 100,000 centimeter

and 1 million year = 1,000,000 year

1\ \text{km/myr} =\frac{100000}{1000000}\ \text{cm/yr}

1\ \text{km/myr} =0.1\ \text{cm/yr}

So, 110\ \text{km/myr} =110\times 0.1\ \text{cm/yr}

110\ \text{km/myr} =11\ \text{cm/yr}

Therefore, 110\ \text{km/myr} =11\ \text{cm/yr}

6 0
3 years ago
Read 2 more answers
What is the momentum of each hockey player? Hockey player 1 has a mass of 65 kg and a velocity of 3.8 m/s
DaniilM [7]

Answer:

Momentum of  hocking player 1: 247\ kg\ m/s

Hockey player 2: =249.4\ kg\ m/s

Step-by-step explanation:

For first hockey player :

Given that

mass (m) =65\ kg

Velocity (v) =3.8\ m/s

p=mv\................(1)

where p is momentum

put the value in equation (1)

p=65\times3.8\\\\p=247kg\times m/s

For second hockey player :

Given that

mass (m) =58\ kg

velocity (v) =4.3\ m/s

p=mv\ ...............(2)

Where p is momentum

put the value in equation (2)

p=58\times4.3\\p=249.4\ kg\times m/s

6 0
3 years ago
There are 25 students that would like to go on a field trip, but only 18 may go. How many different combinations of students cou
Naya [18.7K]

480700. The different combinations of students that could go on the trip with a total of 25 student, but only 18 may go, is 480700.

The key to solve this problem is using the combination formula nC_{r}=\frac{n!}{r!(n-r)!}. This mean the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.

The total of students is n and the only that 18 students may go is r:

25C_{18}=\frac{25!}{18!(7!)}=480700

6 0
3 years ago
C ( , )D ( , ) E ( , ) F ( , )
Alex777 [14]

As shown in the question, the translation changes the points as follows:

(x,y)\rightarrow(x+2,y-2)

Therefore:

\begin{gathered} C(-5,-1)\rightarrow C^{\prime}(-3,-3) \\ D(-4,3)\rightarrow D^{\prime}(-2,1) \\ E(-3,2)\rightarrow E^{\prime}(-1,0) \\ F(-2,0)\rightarrow F^{\prime}(0,-2) \end{gathered}

8 0
1 year ago
Other questions:
  • A recipe for krispy rice treats calls for 6 cups of rice cereal and 40 large marshmallows. You want to make a larger batch of go
    11·2 answers
  • Movie tickets for an adult and three children cost $20. an adult's ticket costs $2 more than a child's ticket. find the cost of
    14·1 answer
  • I just need #31 and #33 answered please.
    5·1 answer
  • What is the p value definition
    8·1 answer
  • In which direction will the parable open x=53(y+17)^2-41
    14·1 answer
  • A wall of a building is made from blocks that are each 1 cubic foot.
    7·1 answer
  • It took a car 3 days to travel 1068 miles. What was this car's average speed, in miles per hour? (round to the nearest mile per
    8·2 answers
  • I need help and you don't have to show your work
    15·1 answer
  • Help help help help help help help​
    7·1 answer
  • John needs to put the set of numbers below in ascending order.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!