Ask question

Ask question

All categories

3 years ago

15

Solve for p. 2(p + 1) = 18

1 answer:

n200080 [17]3 years ago

7 0

Answer:

p = 8

Step-by-step explanation:

Subtract 18 from behind the equal sign to cancel it out. This leaves you with 2(p+1)- 18= 0.

Next you'll need to pull out the terms to work with the beginning of the problem. 2(p+1)- 18= 0 would turn into 2p - 16 = 2(p - 8).

This would leave you with 2= 0, but that's not true so continue on to the variable.

So p - 8= 0 making the answer p = 8

You might be interested in

Which of the following is a true statement?

nadya68 [22]

It's D. That is the only true statement.

5 0

3 years ago

Read 2 more answers

- Ms. McNeil buys 2.4 gallons of gasoline. The total cost is $7.56. The

Brilliant_brown [7]

Answer:

The price of one gallon of gasoline is $3.15

Step-by-step explanation:

If the lady buys 2.4 gallons of gasoline for a total of $7.56, then as the problem suggests, one can find the unknown price of gasoline per gallon (p) by solving the equation for the unknown "p":

2.4 p = 7.56

then divide both sides by 2.4 to isolate the unknown "" on one side of the equal sign:

p = 7.56/2.4

p = $3.15

so this is the price per gallon of gasoline.

3 0

3 years ago

9.35 as a fraction in simpliest form

Lana71 [14]

We know that
the number $9.35$
is equal to
$9+0.35$
and
$0.35$ is equal to
$35/100$
divide by 5 both members
$\frac{35}{100} = \frac{7}{20}$

therefore

the number $9.35$ is equal to $9 \frac{7}{20}$

8 0

3 years ago

Read 2 more answers

ILL GIVE U BRAINLYIST

Amiraneli [1.4K]

B the person above me is right

7 0

3 years ago

Find all the zeroes of the equation(with simple steps).

uysha [10]

<u>Answer-</u>

<em>The zeros are, $5,\ -5,\ 4i,\ -4i$ </em>

<u>Solution-</u>

$\Rightarrow -3x^4+27x^2+1200=0$

$\Rightarrow -3(x^2)^2+27(x^2)+1200=0$

Here,

a = -3, b = 27, c = 1200

So,

$x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}$

$=\dfrac{-27\pm \sqrt{729+14400}}{-6}$

$=\dfrac{-27\pm 123}{-6}$

$=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}$

$=\dfrac{96}{-6},\ \dfrac{-150}{-6}$

$=-16,\ 25$

So,

$\Rightarrow x^2=25,\ -16$

$\Rightarrow x=\sqrt{25},\ \sqrt{-16}$

$\Rightarrow x=5,\ -5,\ 4i,\ -4i$

8 0

3 years ago